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Crank
3 years ago
11

The quadratic function y = –10x2 + 160x – 430 models a store’s daily profit (y) for selling a T-shirt priced at x dollars. What

equation do you need to solve to find the selling price or prices that would generate $50 in daily profit? What method would you use to solve the equation?
Mathematics
2 answers:
Likurg_2 [28]3 years ago
7 0

Answer:

Replace y in the equation with 50: (50 = -10x2 +160x - 430) Use factoring to solve the equation. After writing the equation in standard form and dividing each side by -10, it is easy to factor as 0 = (x - 4)(x - 12).

inn [45]3 years ago
5 0

<span><span> x2-16x+48=0</span> </span>Two solutions were found :<span> x = 12 x = 4</span>

Step by step solution :<span>Step  1  :</span>Trying to factor by splitting the middle term

<span> 1.1 </span>    Factoring <span> x2-16x+48</span> 

The first term is, <span> <span>x2</span> </span> its coefficient is <span> 1 </span>.
The middle term is, <span> -16x </span> its coefficient is <span> -16 </span>.
The last term, "the constant", is <span> +48 </span>

Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 1</span> • 48 = 48</span> 

Step-2 : Find two factors of  48  whose sum equals the coefficient of the middle term, which is  <span> -16 </span>.

<span><span>     -48   +   -1   =   -49</span><span>     -24   +   -2   =   -26</span><span>     -16   +   -3   =   -19</span><span>     -12   +   -4   =   -16   That's it</span></span>


Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -12  and  -4 
                     <span>x2 - 12x</span> - 4x - 48

Step-4 : Add up the first 2 terms, pulling out like factors :
                    x • (x-12)
              Add up the last 2 terms, pulling out common factors :
                    4 • (x-12)
Step-5 : Add up the four terms of step 4 :
                    (x-4)  •  (x-12)
             Which is the desired factorization

<span>Equation at the end of step  1  :</span> (x - 4) • (x - 12) = 0 <span>Step  2  :</span>Theory - Roots of a product :

<span> 2.1 </span>   A product of several terms equals zero.<span> 

 </span>When a product of two or more terms equals zero, then at least one of the terms must be zero.<span> 

 </span>We shall now solve each term = 0 separately<span> 

 </span>In other words, we are going to solve as many equations as there are terms in the product<span> 

 </span>Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

<span> 2.2 </span>     Solve  :    x-4 = 0<span> 

 </span>Add  4  to both sides of the equation :<span> 
 </span>                     x = 4 

Solving a Single Variable Equation :

<span> 2.3 </span>     Solve  :    x-12 = 0<span> 

 </span>Add  12  to both sides of the equation :<span> 
 </span>                     x = 12 

Supplement : Solving Quadratic Equation Directly<span>Solving <span> x2-16x+48</span>  = 0 directly </span>

Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic Formula

Parabola, Finding the Vertex :

<span> 3.1 </span>     Find the Vertex of   <span>y = x2-16x+48</span>

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<h2>58°</h2>

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Keywords: linear equation, substitution method

Learn more about linear equations at:

  • brainly.com/question/10557938
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#LearnwithBrainly

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