Answer:
13.5 answer is 13.5 and one cost 4.5
I don't see a drawing of the quadrilaterals, so I don't know what the perimeter of quadrilateral P is. But whatever the perimeter of P is, Q will be 1/3 of that. Perimeter is a length, so even though it may pertain to a 2-dimensional object, it is still a 1-dimensional, linear measure. When two objects are similar (same shape, but scaled up or down by a scale factor), all corresponding linear measures have the same scale factor.
If you were asked about area or volume, that would be a different matter. In the case of area, you would square the scale factor, and in the case of volume, you would cube the scale factor.
Answer:
5/7
Step-by-step explanation:
A common factor of 8 can be canceled from numerator and denominator.
40/56 = (5·8)/(7·8) = (5/7)·(8/8) = (5/7)·1 = 5/7
_____
Since you know your multiplication tables, you know that 40 and 56 are both multiples of 8.
__
If you don't know your multiplication tables, you can find the greatest common divisor (GCD) of the two numbers and divide each by that. The GCD can be found using Euclid's algorithm. For that, you divide the larger by the smaller and use the remainder as the new smaller number. The original smaller number is now the larger number. For these numbers, that looks like ...
56 ÷ 40 = 1 r 16
40 ÷ 16 = 2 r 8
16 ÷ 8 = 2 r 0 . . . . . the zero remainder signals that the divisor (8) is the GCD
Now, your fraction is ...
(40/8) / (56/8) = 5/7
Answer:
The answer is 
.
Step-by-step explanation:
First, it is important to recall that the group law is not commutative in general, so we cannot assume it here. In order to solve the exercise we need to remember the axioms of group, specially the existence of the inverse element, i.e., for each element 
there exist another element, denoted by 
such that 
, where 
stands for the identity element of G.
So, given the equality 
we make a left multiplication by 
and we obtain:
But, 
. Hence, 
.
Now, in the equality we make a right multiplication by 
, and we obtain
.
Recall that 
and 
. Therefore,
.
