Answer:
C
Step-by-step explanation:
(-2x+9-3x-4)
-2x-3x+9-4
-5x+5
Answer:
2 hours, 150 miles
Step-by-step explanation:
The relation between time, speed, and distance can be used to solve this problem. It can work well to consider just the distance between the drivers, and the speed at which that is changing.
<h3>Separation distance</h3>
Jason got a head start of 20 miles, so that is the initial separation between the two drivers.
<h3>Closure speed</h3>
Jason is driving 10 mph faster than Britton, so is closing the initial separation gap at that rate.
<h3>Closure time</h3>
The relevant relation is ...
time = distance/speed
Then the time it takes to reduce the separation distance to zero is ...
closure time = separation distance / closure speed = 20 mi / (10 mi/h)
closure time = 2 h
Britton will catch up to Jason after 2 hours. In that time, Britton will have driven (2 h)(75 mi/h) = 150 miles.
__
<em>Additional comment</em>
The attached graph shows the distance driven as a function of time from when Britton started. The distances will be equal after 2 hours, meaning the drivers are in the same place, 150 miles from their starting spot.
So you know that 30 + 30 + w + w = P. We also know the area is 240 square feet. Divide 240 by 30 to find the width of the area. 240 / 30 = 8. w = 8. So add 30 + 30 + 8 + 8 to find that P = 76. HOWEVER, remember that George is using part of his house as a wall instead of a fence. So subtract 8 from 76 to get 68 ft. George will need 68 ft. of fencing for his dog run.
Answer: B
Step-by-step explanation:
Please add a photo so we can understand what you mean and your question.