Answer:
sqrt(2)/2
Step-by-step explanation:
Given tan(x)=2-cot(x), find sin(x).
Rewrite in terms of sine and cosine:
sin(x)/cos(x)=2-cos(x)/sin(x)
Multiply both sides by cos(x)sin(x):
sin^2(x)=2sin(x)cos(x)-cos^2(x)
Rewrite cos^2(x) using the identity sin^2(x)+cos^2(x)=1:
sin^2(x)=2sin(x)cos(x)-(1-sin^2(x))
Distribute:
sin^2(x)=2sin(x)cos(x)-1+sin^2(x)
Subtracting sin^2(x) on both sides:
0=2sin(x)cos(x)-1
Add 1 on both sides:
1=2sin(x)cos(x)
Use identity sin(2x)=2sin(x)cos(x) to rewrite right:
1=sin(2x)
Since sin(pi/2)=1, then 2x=pi/2.
Dividing both sides by 2 gives x=pi/4.
So sin(pi/4)=sqrt(2)/2
Substitute 2x+1 where y is in the equation:
9x-2(2x+1)=8
Then distribute the -2(2x+1)
9x-4x+2=8
Then combine like terms (the x)
5x+2=8
Then do -2 on both side of the equation sign
5x+2=8
- 2 -2
Then you'd get
5x=6
Then divide 5 on both sides
X= 1.2
Answer:
A. Air that is breathed in :)
Answer:
correct option is C) 2.8
Step-by-step explanation:
given data
string vibrates form = 8 loops
in water loop formed = 10 loops
solution
we consider mass of stone = m
string length = l
frequency of tuning = f
volume = v
density of stone = 
case (1)
when 8 loop form with 2 adjacent node is 
so here
..............1
and we know velocity is express as
velocity = frequency × wavelength .....................2
= f × 
here tension = mg
so
= f × ..........................3
and
case (2)
when 8 loop form with 2 adjacent node is
..............4
when block is immersed
equilibrium eq will be
Tenion + force of buoyancy = mg
T + v × × g = mg
and
T = v × - v × × g
from equation 2
f × 
= f × 
.......................5
now we divide eq 5 by the eq 3
solve irt we get
so
relative density 
relative density = 2.78 ≈ 2.8
so correct option is C) 2.8
Answer:C
Step-by-step explanation: 7+5=12 12x9.25=111.00
