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FrozenT [24]
3 years ago
13

This is stupid I know lol but I'm having a hard time remembering the difference between a histogram and a bar graph. Can someone

please help me find a way for me to remember the differences?

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
6 0

<u>In Bar Graphs;</u>

- Bars have equal space

- One the y-axis, we have numbers & on the x-axis, we have data which can be anything.

<u> In Histograms;</u>

- Bars are fixed

- On the y-axis, we have numbers & and on the x-axis, we have data which in continuous & will always be number.

<u>An easy way you can remember the difference is looking at the spaces of the bars. </u>

<em>A bar graph has gaps</em>

<em>A histogram has no gaps.</em>

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Please can someone help me with this question
sasho [114]

<em>Answer:</em>

<em>r = -</em>\frac{6a}{1-5m^2}<em />

<em>Step-by-step explanation:</em>

<em>Rewrite the equation as </em>\sqrt{x} 6a+r/5r<em>  = m</em>

<em>Remove the radical on the left side of the equation by squaring both sides of the equation.</em>

<em>(</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> = m^2</em>

<em>Then, you simplify each of the equation. </em>

<em>Rewrite: (</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> as </em>\frac{6a+r}{5r} = m^{2}<em />

<em>Remove any parentheses if needed.</em>

<em>Solve for r. </em>

<em>Multiply each term by r and simplify."</em>

<em>Multiply both sides of the equation by  5.</em>

<em>6a+r= m^2r⋅(5)</em>

<em>Remove parentheses.</em>

<em>Move 5   to the left of (m ^2)  r </em>

<em>6a+r=5m^2)r</em>

<em>Subtract  5m^2)r  from both sides of the equation.</em>

<em>6a+r-5m^2)r=0</em>

<em>Subtract  6a  from both sides of the equation.</em>

<em>r-5m^2)r=-6a</em>

<em>Factor  r out of  r-5m^2)r  </em>

<em>r(1-5m^2)=-6a</em>

Divide each term by 1-5m^2 and simplify.

r = - \frac{6a}{1-5m^2}

There you go, hope this helps!

4 0
3 years ago
Devin is buying 2 concert tickets. The concert tickets have a regular price of $40 each. Devin has a coupon that gives a 5% disc
Svetach [21]

Given :

Devin is buying 2 concert tickets. The concert tickets have a regular price of $40 each.

Devin has a coupon that gives a 5% discount off of the regular price of the tickets. He will then pay a 10% purchasing fee on the discounted price of the tickets.

To Find :

Devin's total cost of the two tickets after the discount and the fee.

Solution :

Discount on price, D = 40×0.05 = $2 .

Price of product after discount, P = $( 40 - 2 ) = $38 .

Now, total price after adding purchasing fee is :

T = P + (P×0.10)

T = 38 + (38×0.10)

T = 38 + 3.8

T = $41.8

Therefore, Devin's total cost of the two tickets after the discount and the fee is $41.8 .

Hence, this is the required solution.

5 0
3 years ago
I need help
Ilia_Sergeevich [38]

Answer:

310

Step-by-step explanation:

A circle is 360 degrees

50 +x = 360

x = 360-50

x = 310

3 0
2 years ago
Write an expression, using an exponent, that is equivalent to 9 x 9 x 9 x 9 x 9 x 9 x 9.
Pavel [41]

Answer:

9^{2}

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Solve the system of equations 2x + 3y = 40 and –2x + 2y = 20.
Flura [38]
2x + 3y = 40
+
-2x + 2y = 20
___________                  Adding both equations

0x + 5y  = 60
____________


5y = 60
y = 60/5 = 12

y = 12.

Since we have gotten y =12, and the only option with that is option D.

So we don't have to solve for x.

<span>The answer is D.</span>
7 0
3 years ago
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