-3(1+6r)+12=14. solve for r
2 answers:
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Answer:
B)3x^2 (4*x^2 + 2x + 6)
Step-by-step explanation:
Step 1: Find the Greatest common factor of the given expression.
12x^4 + 6x^3 + 18x^2
The above expression can be written as .
= 2*2*3*x^4 + 2*3*x^3 + 2*3*3*x^2
Here 3x^2 is prime factor
Step 2: Let's take out the 3 and write the remaining terms in the parenthesis.
= 3x^2 (2*2*x^2 + 2x + 2*3)
= 3x^2 (4x^2 + 2x + 6)
Therefore, the answer is B)3x^2 (4*x^2 + 2x + 6)
Thank you.
Step-by-step explanation:
Angles in the same segment. The angles at the circumference subtended by the same arc are equal. More simply, angles in the same segment are equal.
Picture 1 a° = a° they are the same
Picture 2 p= 52° q= 40° Angles in the same segment are equal. if they ask you to calculate you just show both angles p= 52 and q=40.
Picture 3 + 4 Let the obtuse angle MOQ = 2x.
Using the circle theorem, the angle at the centre is twice the angle at the circumference.
Therefore picture 4 tells us and proves;
Angle MNQ = x and angle MPQ = x.
Picture 5
A cyclic quadrilateral is a quadrilateral drawn inside a circle. Every corner of the quadrilateral must touch the circumference of the circle.
The second shape is not a cyclic quadrilateral. One corner does not touch the circumference.
Picture 6
The opposite angles in a cyclic quadrilateral add up to 180°.
a + c = 180°
b + d = 180°
Picture 7
Example
Calculate the angles a and b.
The opposite angles in a cyclic quadrilateral add up to 180°.
This is a picture that couldn't be added but has a quadrilateral occupying half the triangle consisting of 3 arcs the middle one was 140 and proved part of one triangle. The x (a) missing angle showed below a = 180-60 = 120 °
So hopefully this will help you remember the format here for quadrilateral shapes within a circle.
b = 180 - 140 = 40°
a = 180 - 60 = 120°
