The general form of an equation is
. Solving for (5+X)(5-X)=7 by multiplying the factors and subtratcting 7 on both sides gives the equation
, so
A = 1
B = 0
C = -18
HAT MATH ARE U IN
i got part of it but it lost me the
<span>differ part of land is 49,500 but it lost meh hope it helps gl</span>
It wants it to be in slope-intercept form.
y=mx+b
We have to first find the slope and plug it into point-slope form.
y-y1=m(x-x1)
Find the slope of the second line. (I did this one first on accident)
Rise/run= 3/1= 3 The slope is 3. Plug that in along with the point (0,3)
y-3=3(x-0)
y-3=3x
Add 3 to the other side.
y= 3x +3 <- <em>for the second line</em><em>
</em>
Now, the second.
rise/run= 1/2= .5 Use point (6,0)
y-0=.5(x-6)
y= .5x-3
y=.5x-3 <- for the first line
I hope this helps!
~kaiker
Answer:
(x+1)(x-1)(x+3)(x-3)
Step-by-step explanation:
x4-10x^2+9
Group expression so that the coefficients of the x^2 terms add up to +9.
= x^4 -9x^2 - x^2+9
match coefficients in both groups
= x^4 -9x^2 - (x^2-9)
factor each group
= x^2 (x^2-9) - 1(x^2-9)
now factor out the common factor (x^2-9)
= (x^2-1)(x^2-9)
Finally, factor each quadratic factor
= (x+1)(x-1)(x+3)(x-3)
<u><em>The additive identity property </em></u>. . . is being used here because no matter what the value is, whenever you add zero (0) to it, you'll always get the value your started with.
