9514 1404 393
Answer:
a.
Step-by-step explanation:
For an even-index radical, ...
![\sqrt[n]{x^n}=|x|\qquad\text{n even}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5En%7D%3D%7Cx%7C%5Cqquad%5Ctext%7Bn%20even%7D)
This lets us simplify the given expression as follows:
![\sqrt[4]{81x^6y^4}-|y|\sqrt[4]{x^6}-\sqrt[4]{16x^2}=\sqrt[4]{(3xy)^4x^2}-|y|\sqrt[4]{x^4x^2}-\sqrt[4]{2^4x^2}\\\\=3|xy|\sqrt[4]{x^2}-|xy|\sqrt[4]{x^2}-2\sqrt[4]{x^2}=\boxed{2|xy|\sqrt[4]{x^2}-2\sqrt[4]{x^2}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B81x%5E6y%5E4%7D-%7Cy%7C%5Csqrt%5B4%5D%7Bx%5E6%7D-%5Csqrt%5B4%5D%7B16x%5E2%7D%3D%5Csqrt%5B4%5D%7B%283xy%29%5E4x%5E2%7D-%7Cy%7C%5Csqrt%5B4%5D%7Bx%5E4x%5E2%7D-%5Csqrt%5B4%5D%7B2%5E4x%5E2%7D%5C%5C%5C%5C%3D3%7Cxy%7C%5Csqrt%5B4%5D%7Bx%5E2%7D-%7Cxy%7C%5Csqrt%5B4%5D%7Bx%5E2%7D-2%5Csqrt%5B4%5D%7Bx%5E2%7D%3D%5Cboxed%7B2%7Cxy%7C%5Csqrt%5B4%5D%7Bx%5E2%7D-2%5Csqrt%5B4%5D%7Bx%5E2%7D%7D)
Answer:
Point N(4, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Coordinates (x, y)
- Functions
- Function Notation
- Terms/Coefficients
- Anything to the 0th power is 1
- Exponential Rule [Rewrite]:
- Exponential Rule [Root Rewrite]:
<u>Calculus</u>
Derivatives
Derivative Notation
Derivative of a constant is 0
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Derivative Rule [Chain Rule]: ![\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%20%3Df%27%28g%28x%29%29%20%5Ccdot%20g%27%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>
<u />
<u />
<u />
<u />
<u />
<u>Step 2: Differentiate</u>
- [Function] Rewrite [Exponential Rule - Root Rewrite]:

- Chain Rule:
![\displaystyle y' = \frac{d}{dx}[(x - 3)^{\frac{1}{2}}] \cdot \frac{d}{dx}[x - 3]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%27%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5B%28x%20-%203%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5D%20%5Ccdot%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bx%20-%203%5D)
- Basic Power Rule:

- Simplify:

- Multiply:

- [Derivative] Rewrite [Exponential Rule - Rewrite]:

- [Derivative] Rewrite [Exponential Rule - Root Rewrite]:

<u>Step 3: Solve</u>
<em>Find coordinates</em>
<em />
<em>x-coordinate</em>
- Substitute in <em>y'</em> [Derivative]:

- [Multiplication Property of Equality] Multiply 2 on both sides:

- [Multiplication Property of Equality] Multiply √(x - 3) on both sides:

- [Equality Property] Square both sides:

- [Addition Property of Equality] Add 3 on both sides:

<em>y-coordinate</em>
- Substitute in <em>x</em> [Function]:

- [√Radical] Subtract:

- [√Radical] Evaluate:

∴ Coordinates of Point N is (4, 1).
Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Derivatives
Book: College Calculus 10e
The multiplication of the expression (x² + 3x + 2) (2x² + 3x + 1) is 2x⁴ + 9x³ + 14x² + 9x + 2
<h3>Multiplication</h3>
(x² + 3x + 2) (2x² + 3x + 1)
= 2x⁴ + 3x³ + x² + 6x³ + 9x² + 3x + 4x² + 6x + 2
= 2x⁴ + 3x³ + 6x³ + x² + 9x² + 4x² + 3x + 6x + 2
= 2x⁴ + 9x³ + 14x² + 9x + 2
Learn more about multiplication:
brainly.com/question/10873737
#SPJ1
Answer:
9.7
Step-by-step explanation: