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kolezko [41]
3 years ago
5

What is the simplified form of the following expression?

Mathematics
1 answer:
Flura [38]3 years ago
7 0
If the question is (n^5)(n^2) then the answer is n^7
You add exponents when multiplying the expressions like this

The rule used is
a^b*a^c = a^(b+c)
You might be interested in
X < -10/3 or x > 2/3
Fittoniya [83]

Hello! :)

Here is a graph for x < -10/3 or x > 2/3.

THEDIPER

6 0
3 years ago
A group of 7 people want to equally share 33 1/4 ounces of cake. How much will one person get
AURORKA [14]
Each person will get 4.75 ounces of cake. You just divide 33 1/4 by 7. 
Hope this helps! :D

~PutarPotato
5 0
3 years ago
on monday, roger drove to work in 20 minutes. on tuesday, he averaged 15 miles per hour more, and it took him 6 minutes less to
ch4aika [34]
Let the distance to his office be x, then
On monday, speed = x/20 miles per minutes = 3x miles per hour
On tuesday, speed = (3x + 15) miles per hour
Time = distance / speed
(20 - 6)/60 hours = x/(3x + 15) hours
7/30 = x/(3x + 15)
7(3x + 15) = 30x
21x + 105 = 30x
30x - 21x = 105
9x = 105
x = 105/9 = 11.7 miles

Therfore he travels an average of 11.7 miles to work.
7 0
3 years ago
The amount of trout y (in tons) caught in a lake from 1995 to 2014 can be modeled by the equation y = -0.08x2 + 1.6x + 10, where
Lapatulllka [165]
For this case, the first thing we want to do is substitute the value of y = 15 in the equation.
 We have then:
 15 = -0.08x ^ 2 + 1.6x + 10
 Rewriting we have:
 0 = -0.08x ^ 2 + 1.6x + 10 - 15
 0 = -0.08x ^ 2 + 1.6x - 5
 The solutions are:
 x1 = 3.876275643042054
 x2 = 16.123724356957947
 Nearest whole number:
 x1 = 4
 x2 = 16
 were about 15 tons of trout caught in the lake in the years:
 1995 + 4 = 1999
 1995 + 16 = 2011
 Answer:
 The year 1999 and the year 2011
3 0
3 years ago
In the year 2003, a company made $6.8 million in profit. For each consecutive year after that, their profit increased by 13%. Ho
LenKa [72]

Answer:

$7.7 million

Step-by-step explanation:

Given: $6.8 million profit made by company.

           13% increase in profit every year.

Now, finding the company´s profit in the year of 2006.

As we know there is 13% increase in profit.

∴ Profit increase= \frac{13}{100} \times 6.8= \$ 0.884

Next adding company´s profit with increase in profit to get profit in the year 2006.

∴ 6.8+0.884= \$ 7.684 ≅ $7.7

The company´s profit in the year 2006 is $7.7 million.

6 0
3 years ago
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