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aniked [119]
3 years ago
8

Type the correct answer in the box. Use numerals instead of words.

Mathematics
1 answer:
Pani-rosa [81]3 years ago
8 0

Answer:

Step-by-step explanation:

7- \sqrt[3]{2-x} =12

we have to just keep in mind to do the same operation to both sides of the equal sign

7-7- \sqrt[3]{2-x} =12-7 ; subtract 7 from both sides

- \sqrt[3]{2-x} = 5 ; multiply both sides by -1

\sqrt[3]{2-x} = -5 ; raise both sides to the power 3

2-x = (-5)³

2-x = -125 ; subtract 2 from both sides

-x = -125-2

-x =-127; multiply both sides by -1

x= 127

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Solve the equation. Round to the nearest hundredth. Show work.
muminat

Answer:

Final answer is approx x=0.16.

Step-by-step explanation:

Given equation is 2.8\times 13^{4x} +4.8 = 19.3

Now we need to solve equation 2.8\times 13^{4x} +4.8 = 19.3 and round to the nearest hundredth.

2.8\times 13^{4x} +4.8 = 19.3

2.8\times 13^{4x} = 19.3-4.8

2.8\times 13^{4x} = 14.5

13^{4x} = \frac{14.5}{2.8}

13^{4x} = 5.17857142857

\log(13^{4x}) = \log(5.17857142857)

4x \log(13) = \log(5.17857142857)

4x = \frac{\log(5.17857142857)}{\log\left(13\right)}

4x = 0.641154659628

x = \frac{0.641154659628}{4}

x = 0.160288664907

Round to the nearest hundredth.

Hence final answer is approx x=0.16.

4 0
3 years ago
I need help with this problemmmm.
AlladinOne [14]

Answer:

x = 1 1/6, x = 1.16

There you go! :D

3 0
3 years ago
Read 2 more answers
The sum of three consecutive intgers is 72 find the smallest integer
zmey [24]
23 + 24 + 25 = 72
23 is the answer
5 0
3 years ago
Read 2 more answers
What is the percent of increase from 106 miles to 122 miles?
Elis [28]

Answer:

15.094 %

Step-by-step explanation:

[(122 - 106) /106] 100

(16/106) 100

(0.15094)x100

15.094

8 0
3 years ago
Let f(x) = log(x). Find values of a such that f(kaa) = kf(a).
meriva

Answer:

a = k^{\frac{1}{k-2}}

Step-by-step explanation:

Given:

f(x) = log(x)

and,

f(kaa) = kf(a)

now applying the given function, we get

⇒ log(kaa) = k × log(a)

or

⇒ log(ka²) = k × log(a)

Now, we know the property of the log function that

log(AB) = log(A) + log(B)

and,

log(Aᵇ) = b × log(A)

Thus,

⇒ log(k) + log(a²) = k × log(a)         (using log(AB) = log(A) + log(B) )

or

⇒ log(k) + 2log(a) = k × log(a)            (using log(Aᵇ) = b × log(A) )

or

⇒ k × log(a) - 2log(a) = log(k)

or

⇒ log(a) × (k - 2) = log(k)

or

⇒ log(a) = (k - 2)⁻¹ × log(k)

or

⇒ log(a) = \log(k^{\frac{1}{k-2}})          (using log(Aᵇ) = b × log(A) )

taking anti-log both sides

⇒ a = k^{\frac{1}{k-2}}

3 0
3 years ago
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