This is a probability problem with two dependent events and conditional probability. Note that after the first donut is chosen, it is not replaced into the data set, so only 23 donuts remain. If we set A=selection of a lemon-filled, and B=selection of a custard-filled, then P(A and B) = P(A)*P(B|A), where P(B|A) means the probability of B happening given that A has already occurred.P(A) = 8/24 = 1/3 = 0.333333P(B|A) = 12/23 = 0.521739P(A and B) = 1/3(12/23) = 12/69 = 0.1739130435 or 17.4%
https://www.wyzant.com/resources/answers/296921/find_the_probability_of_selecting_a_a_lemon_filled_d...
The answer to this would be B. Why? Because when you plug 33/9 into a calculator you get 3.66666666666 continuous. I hope this helps!
7 over 8 can be seen as

or 7÷8.
This is what this question will look like on a calculator.

As you can see, you will only get 0.875 so your answer will be terminating.
Terminating = Answer Stops
ex.) 0.784 or 0.25
Repeating = Answer Repeats
ex.) 0.5555... or 1.33...
Y=1/2x+5. Because 6-5 is 1 over 2-0 is 2 so 1/2 and the y intercept is 5 because that’s where x is 0