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Korvikt [17]
3 years ago
6

There are a total of 2,512 people attending the fun fair. ⅝ of the attendees are students and ¼ are parents. The rest of the peo

ple attending are people who live in the neighborhood. How many of the attendees are people living in the neighborhood?
Mathematics
1 answer:
Alex787 [66]3 years ago
4 0

Answer:

314

Step-by-step explanation:

628 are parents

1570 are students

2198 total.

2512-2198

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Although it is now extinct, the Carolina parakeet was last seen in Florida in 1920. Back then, large areas of habitat were logge
Scrat [10]

Answer:

a

Step-by-step explanation:

7 0
3 years ago
1.What is the slope of (0,2) and (-8,-8). What is the slope of (-8,-5) and (8,15)
ss7ja [257]

Answer:

Slope of (0,2) and (-8,-8):    5/4

Slope of (-8,-5) and (8,15):   5/4

Both slopes are 5/4

m = 5/4

Step-by-step explanation:

To find the slope:

1. Use the formula  m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}} .

2. Assign point 1 and point 2

3. State (x₁ , y₁) and (x₂, y₂)

4. Substitute x₁ , y₁, x₂, and y₂ into the formula

5. Solve

Slope of (0,2) and (-8,-8):

Point 1: (0,2)        x₁ = 0     y₁ = 2

Point 2: (-8,-8)     x₂ = -8   y₂ = -8

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}         Formula for slope

m = \frac{-8-2}{-8-0}           Substituted points

m = \frac{-10}{-8}          Simplified the subtraction then the negatives

m = \frac{10}{8}          Reduce fraction by dividing top and bottom by 2

m = \frac{5}{4}              First slope

Slope of (-8,-5) and (8,15):

Point 1: (-8,-5)     x₁ = -8    y₁ = -5

Point 2: (8,15)     x₂ = 8     y₂ = 15

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}            Formula for slope

m = \frac{15-(-5)}{8-(-8)}         Substituted points

m = \frac{15+5}{8+8}             Simplified the subtraction into addition

m = \frac{20}{16}                Reduce fraction (divide top and bottom by 4)

m = \frac{5}{4}                 Second slope

3 0
3 years ago
.......Help Please......
padilas [110]

Answer:

  • largest: R
  • smallest: K

Step-by-step explanation:

The slope of the graph at x=0 is related to the value of b. It is also proportional to the value of <em>a</em>, which is the same for all but curve B. The red curve R has the largest slope at x=0, (much larger than 3/4 the slope of curve B), so curve R has the greatest value of <em>b</em>.

Similarly, the smallest value of <em>b</em> will correspond to the curve with the smallest (most negative) slope. That would be curve K. Curve K has the smallest value of <em>b</em>.

7 0
3 years ago
Find a second degree polynomial f(x) (of the form ax^2+b^x+2 that has a local extrema at (−5/8,7/16).
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JwffywvSHBvbufuhzs vh  ge wVbj aj
6 0
4 years ago
The number of cars running a red light in a day, at a given intersection, possesses a distribution with a mean of 2.4 cars and a
liberstina [14]

Answer:

The sampling distribution of the sample mean is:

\bar X\sim N(\mu_{\bar x}=2.4,\ \sigma_{\bar x}=0.40)

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

Let <em>X</em> = number of cars running a red light in a day, at a given intersection.

The information provided is:

E(X)=\mu=2.4\\SD(X)=\sigma=4\\n=100

The sample selected is quite large, i.e. <em>n</em> = 100 > 30.

The Central limit theorem can be used to approximate the sampling distribution of the sample mean number of cars running a red light in a day, by the Normal distribution.

The mean of the sampling distribution of the sample mean is:

\mu_{\bar x}=\mu=2.4

The standard deviation of the sampling distribution of the sample mean is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{4}{\sqrt{100}}=0.40

The sampling distribution of the sample mean is:

\bar X\sim N(\mu_{\bar x}=2.4,\ \sigma_{\bar x}=0.40)

8 0
3 years ago
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