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yawa3891 [41]
2 years ago
9

PLEASE HELP ME I GIVE THANKS

Mathematics
2 answers:
natali 33 [55]2 years ago
4 0
( 6 / 7 )x > 12 ;
x > ( 12 × 7 ) / 6 ;
x > 84 / 6 ;
x > 14 ; 
x∈( 14 , + oo ) ;
The right answer is C.
sattari [20]2 years ago
3 0
C,
It's an open dot because it's not Greater than or equal to sign<span />
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Is 1/3 greater than 5/6
Harman [31]
1/3 or 5/6 

Lets make the fractions into decimals. To make a fraction into decimal you have to divide the numerator by the denominator. The numerator is the top part of a fraction and the denominator is the bottom part of the fraction. 

≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡

Calculations

1/3
1 ÷ 3 =  0.3333.... 

5/6 
5 ÷ 6 = 0.83333...

0.83333... is greater then 0.3333.....
Therefore 5/6 is greater then 1/3 
1/3 is smaller then 5/6 
5 0
2 years ago
Jason wants to create a box with the same volume as the one shown below. He wants the length to be 4 inches. What would be the m
jeyben [28]

Answer:

Width-6

height-3

I determinded the width and the height by counting how many cubic blocks there are up and down.

Step-by-step explanation:

8 0
3 years ago
HELP ME PLZ
nadezda [96]

Answer:

BD does bisect the angle created by ABC, however it does not bisect segment AC. So it really depends on what you are determining the bisection to be.

Step-by-step explanation:

We can tell that it is bisecting the angle since it creates two congruent angles.

We can tell that it does not bisect the segment as AD and CD are not the same length.

5 0
2 years ago
What is the correct equation of the circle with the center (4, 6) and radius 6?
jasenka [17]

I know it's either A B C or D.

6 0
3 years ago
Express with radical signs instead of fractional exponents. Rationalize the denominator.
CaHeK987 [17]

x^{\frac{1}{2}} = \sqrt[2]{x} and 3^{-\frac{1}{2}} = \frac{1}{3^{\frac{1}{2}} } = \frac{1}{\sqrt[2]{3}} so

3^{-\frac{1}{2}} x^{\frac{1}{2}} = \frac{1}{\sqrt{3}} \cdot \sqrt{x}  = \frac{\sqrt{x}}{\sqrt{3}}

and you rationalize denominator by multiplying numerator and denominatr by \sqrt{3} so that gives--

\frac{\sqrt{x}}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3x}}{3}

Your answer is \frac{\sqrt{3x}}{3}

5 0
3 years ago
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