Answer:
<u><em>(x+5) is not a factor of f(x)</em></u>
Step-by-step explanation:
Step 1 : we solve the equation x +5 = 0
x + 5 = 0 then x = -5
Step 2: we plug in -5 into f(x)
If we get zero then x+5 is a factor of f(x)
If we get a number other than zero then x+5 is not a factor of f(x)
Calculation:
f(-5) = (-5)³ − 4(-5)² + 3(-5) + 7 = - 233
Since we got -233 and not 0
Therefore ,(x+5) is not a factor of f(x)
Answer: ummmmmmm
Step-by-step explanation: teeeeeheeee
idk
GIBE MEH A TANKS
You really just have to round the numbers. Its super simple what number would round to the number that they are saying they are?
Using <u>complex numbers and radicals</u>, it is found that the correct option is C.
When a complex number is a root of a polynomial function, it's conjugate also has to be.
- Hence, since 8i is a root of the function, -8i is also a root.
The same is valid for radicals, as they are in the
format.
- Since
is a root,
is also a root.
Hence, option C is correct.
For more on <u>complex numbers and radicals</u>, you can check brainly.com/question/25173944
Answer:
see explanation
Step-by-step explanation:
Using the sum/ difference → product formula
cos x - cos y = - 2sin(
)sin (
)
sin x - sin y = 2cos (
)sin (
)
Given
(cosA - cosB)² + (sinA - sinB )²
= [ - 2sin(
)sin(
) ]² + [ 2cos(
)sin(
) ]²
= 4sin² (
)sin² (
) + 4cos² (
)sin² (
)
= 4sin² (
)[ sin² (
) + cos² (
) ← sin²x + cos²x = 1
= 4sin² (
) × 1
= 4sin² (
) = right side ⇒ proven