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zloy xaker [14]
3 years ago
15

Dominique works in sales and gets paid $275 per week plus commission. This week he received a total pay of $5075. If his total s

ales was $64000, what percentage commission does Dominique receive?
Mathematics
1 answer:
Lerok [7]3 years ago
6 0

Answer: Bruh

Step-by-step explanation: is that u ratty ;-;

You might be interested in
Is (x+5) A FACTOR OF f(x) = x3 − 4x2 + 3x + 7
AlekseyPX

Answer:

<u><em>(x+5) is not a factor of f(x)</em></u>

Step-by-step explanation:

Step 1 : we solve the equation x +5 = 0

x + 5 = 0 then x = -5

Step 2: we plug in -5 into f(x)

If we get zero then x+5 is a factor of f(x)

If we get a number other than zero then x+5 is not a factor of f(x)

Calculation:

f(-5) =  (-5)³ − 4(-5)² + 3(-5) + 7 = - 233

Since we got -233 and not 0

Therefore ,(x+5) is not a factor of f(x)

8 0
2 years ago
Read 2 more answers
Write the number that makes each number sentence true
andrey2020 [161]

Answer: ummmmmmm

Step-by-step explanation: teeeeeheeee

idk

GIBE MEH A TANKS

6 0
3 years ago
Read 2 more answers
Help don't get any of them. please explain
hammer [34]
You really just have to round the numbers. Its super simple what number would round to the number that they are saying they are?
8 0
3 years ago
Read 2 more answers
A fifth-degree polynomial equation with rational coefficients has the roots 3, 8i, and 7- radical 5. Which are also roots of the
Sliva [168]

Using <u>complex numbers and radicals</u>, it is found that the correct option is C.

When a complex number is a root of a polynomial function, it's conjugate also has to be.

  • Hence, since 8i is a root of the function, -8i is also a root.

The same is valid for radicals, as they are in the \pm format.

  • Since 7 - \sqrt{5} is a root, 7 + \sqrt{5} is also a root.

Hence, option C is correct.

For more on <u>complex numbers and radicals</u>, you can check brainly.com/question/25173944

8 0
2 years ago
Please help me!!!!!​ i need full answer.
salantis [7]

Answer:

see explanation

Step-by-step explanation:

Using the sum/ difference → product formula

cos x - cos y = - 2sin( \frac{x+y}{2})sin (\frac{x-y}{2} )

sin x - sin y = 2cos (\frac{x+y}{2} )sin (\frac{x-y}{2} )

Given

(cosA - cosB)² + (sinA - sinB )²

= [ - 2sin(\frac{A+B}{2})sin(\frac{A-B}{2} ) ]² + [ 2cos(\frac{A+B}{2} )sin(\frac{A-B}{2} ) ]²

= 4sin² (\frac{A+B}{2} )sin² (\frac{A-B}{2} ) + 4cos² (\frac{A+B}{2} )sin² ( \frac{A-B}{2} )

= 4sin² (\frac{A-B}{2} )[ sin² ( \frac{A+B}{2} ) + cos² ( \frac{A+B}{2} ) ← sin²x + cos²x = 1

= 4sin² ( \frac{A-B}{2} ) × 1

= 4sin² ( \frac{A-B}{2} ) = right side ⇒ proven

4 0
4 years ago
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