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3 years ago

Which rigid transformation does not result in a reversed orientation of the original image?

Mathematics

2 answers:

GREYUIT [131]3 years ago

5 0

Answer:

Reflection is a type of transformation which will not result in reversed orientation. This transformation that uses a line that acts like a mirror called the line of reflection which means that with an image reflected in the line.

ehidna [41]3 years ago

4 0

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Paraphin [41]

Answer:

2nd option

Step-by-step explanation:

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3 years ago

Help with this question please! Give explanation! Big points

BigorU [14]

Answer:

$y = 2$

Step-by-step explanation:

This answer is easily found using the Pythagorean Theorem:

${a}^{2} + {b}^{2} = {c}^{2}$

where A and B are the legs, and C is the hypotenuse of the triangle.

${(16)}^{2} + {(6y)}^{2} = {(10y)}^{2} \\ 256 + 36{y}^{2} = 100 {y}^{2} \\ 256 = 64 {y}^{2} \\ \sqrt{256} = \sqrt{64 {y}^{2}} \\ 16 = 8y \\ y = 2$

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3 years ago

If cot theta= 4/3, find csc theta

Marrrta [24]

Answer: Option d.

Step-by-step explanation:

The trigonometric identity needed is:

$csc^2\theta=cot^2\theta+1$

Knowing that $cot\theta=\frac{4}{3}$ :

Substitute it into $csc^2\theta=cot^2\theta+1$ :

$csc^2\theta=(\frac{4}{3})^2+1$

Simplify the expression:

$csc^2\theta=(\frac{4}{3})^2+1\\\\csc^2\theta=\frac{16}{9}+1\\\\csc^2\theta=\frac{25}{9}$

Solve for $csc\theta$ . Apply square root at both sides of the expression:

$\sqrt{csc^2\theta}=\±\sqrt{\frac{25}{9}}$

$csc\theta=\frac{5}{3}$

8 0

3 years ago

A spring stretches in relation to the weight hanging from it all cording to the equation Y equals 0.75X +0.25 where X is the wei

Tomtit [17]

What is the question?

3 0

3 years ago

Solve 2 log3 x + log3 5 =125

zepelin [54]

Answer:

x = √(3^125/ 5)

approx 2.9552445 * 10^29.

Step-by-step explanation:

2 log3 x + log3 5 =125

log3 x^2 + log3 5 = 125

log3 (5x^2) = 125

3^125 = 5x^2

x^2 = 3^125/ 5

x = √(3^125/ 5)

This is a huge number

An approximation of it is 2.9552445 * 10^29.

3 0

3 years ago