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2 years ago

Which ordered pair (x, y) is the solution to the given system of linear equations?

Mathematics

2 answers:

QveST [7]2 years ago

4 0

Answer:(-1,0)

Step-by-step explanation:

3x + 3y=-3. Solve by the elimination method.

-2x+y=2

2(3x + 3y)=-3(2) New equation 6x + 6y=-6

3(-2 + y)=2(3). New equation -6x +3y=6

9y= 0

y=0

6x +6(0)=-6

6x =-6

X=-1

Stella [2.4K]2 years ago

3 0

(-1,0)

y=2x+2 *new equation for second*
3x+3(2x+2)=-3 *plug y into first equation*
3x+(6x+6)=-3 *combine like terms*
9x+6=-3 *bring 6 to the other side by subtracting 6 on both sides*
9x = -9 *divide by 9 to get x by itself*
x = -1

to find y (now that we have x):
-2(-1) +y=2
2+y=2
y=0

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neonofarm [45]

Answer:

(a) $h(t)=\frac{1.3t^2}{2} + 2t +17$

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Step-by-step explanation:

The growth rate of the shrub is given as:

$\frac{dh}{dt} = 1.3t + 2$

Where t=time in years, h=height in centimeters

(a)First, we solve for the height h(t) by integrating.

$\int \frac{dh}{dt} dt= \int (1.3t + 2)dt\\h(t)=\frac{1.3t^2}{2} + 2t +C, $ C a constant of Integration$\\$We sunstitute the initial value to find the value of C$\\$When t=0, h=17cm$\\17=C\\Therefore:\\h(t)=\frac{1.3t^2}{2} + 2t +17$

(b)The shrub are sold after 7 years of growth. Therefore, we determine the value of h(t) when t=7 years.

$h(t)=\frac{1.3t^2}{2} + 2t +17\\h(7)=\frac{1.3*7^2}{2} + 2(7) +17\\=31.85+14+17\\h(7)=62.85cm$

The Shrubs are 62.85cm tall when they are sold.

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