Answer:
why
Step-by-step explanation:
First, rewrite the equation so that <em>y</em> is a function of <em>x</em> :

(If you were to plot the actual curve, you would have both
and
, but one curve is a reflection of the other, so the arc length for 1 ≤ <em>x</em> ≤ 8 would be the same on both curves. It doesn't matter which "half-curve" you choose to work with.)
The arc length is then given by the definite integral,

We have

Then in the integral,

Substitute

This transforms the integral to

and computing it is trivial:

We can simplify this further to

Given equation of the Circle is ,
And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,
Here we can say that ,
• Radius = 5 units
• Centre = (0,0)
Finding distance between the two points :-
Here we can see that the distance of point from centre is less than the radius.
Hence the point lies within the circle .
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Answer:
D
Step-by-step explanation: