Answer:
True, see proof below.
Step-by-step explanation:
Remember two theorems about continuity:
- If f is differentiable at the point p, then f is continuous at p. This also applies to intervals instead of points.
- (Bolzano) If f is continuous in an interval [a,b] and there exists x,y∈[a,b] such that f(x)<0<f(y), then there exists some c∈[a,b] such that f(c)=0.
If f is differentiable in [0,4], then f is continuous in [0,4] (by 1). Now, f(0)=-1<0 and f(4)=3>0. Thus, we have the inequality f(0)<0<f(4). By Bolzano's theorem, there exists some c∈[0,4] such that f(c)=0.
Treat as an equality, except flip the sign direction when yo multiply or divide both sides by a negative number
first distribute
2(4+2x)<u>></u>5x+5
distribute
8+4x<u>></u>5x+5
minus 4x fro both sides
8<u>></u>x+5
minus 5 from both sides
3<u>></u>x
x<u><</u>3
x is less than or equal to 3
Answer:
16*10^7 or 160000000
Step-by-step explanation:
combine whole numbers: 8*2
and combine exponents: 10^-3*10^10=10^7
8*2*10^7
16*10^7
160000000
Solve for the first variable in one of the equations, then substitute the result into the other equation.
a
=
−
2
,
b
=
5
a
=
-
2
,
b
=
5
T
Answer:
dc is garbo. marvel is better
Step-by-step explanation:
