A cable television company randomly calls 200 customers and asks them if they are satisfied with their service

For the linear equation 3x + 7y = 42: a. Determine the slope: b. Determine y- intercept if it exists: c. Express equation in slo

algol13

Answer: The required answers are

(a) the slope of the given line is $-\dfrac{3}{7}.$

(b) y-intercept exists and is equal to 6.

(c) the slope-intercept form of the line is $y=-\dfrac{3}{7}x+6.$

Step-by-step explanation: We are given the following linear equation in two variables :

$3x+7y=42~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We are to :

(a) determine the slope,

(b) determine the y-intercept, if exists

and

(c) express equation in slope-intercept form.

We know that

The SLOPE_INTERCEPT form of the equation of a straight line is given by

$y=mx+c,$ where m is the slope and c is the y-intercept of the line.

From equation (i), we have

$3x+7y=42\\\\\Rightarrow 7y=-3x+42\\\\\Rightarrow y=\dfrac{-3x+42}{7}\\\\\\\Rightarrow y=-\dfrac{3}{7}x+6.$

Comparing with the slope-intercept form, we get

$\textup{slope, m}=-\dfrac{3}{7},\\\\\\\textup{y-intercept, c}=6.$

Thus,

(a) the slope of the given line is $-\dfrac{3}{7}.$

(b) y-intercept exists and is equal to 6.

(c) the slope-intercept form of the line is $y=-\dfrac{3}{7}x+6.$

3 0

3 years ago

4. If DF = 9x - 39, find EF. Help I’m so confused!!!!

topjm [15]

Answer:

EF =58

Step-by-step explanation:

from the illustration,

EF =DF - DE

given that DF =9x-39 , DE =47 EF=3x +10

substitute them into the formula,

3x +10=9x-39 - 47

solving for x

3x +10 =9x -86

grouping like terms

3x - 9x =-86 -10

-6x=-96

dividing through by -6

 $\frac{ - 6x}{ - 6} = \frac{ - 96}{ - 6}$ 

 $x = \frac{96}{6}$ 

 $x = 16$ 

but EF=3x+10

substitute x=16 into it to get the EF

EF= 3(16)+10

EF=48+10

EF=58

6 0

3 years ago

Read 2 more answers

Calculate f(x) for the given domain values.

Maksim231197 [3]

Answer:

See explanation

Step-by-step explanation:

1. The given function is

$f(x) = - 3x$

The domain values are: x=0, 2, -1, 4, -2

When x=0

$f(0) = - 3 \times 0 = 0$

When x=2,

$f(x) = - 3 \times 2 = - 6$

When x=-1

$f(x) = - 3 \times - 1 = 3$

When x=4

$f(4) = - 3 \times 4 = - 12$

When x=-2

$f( - 2) = - 3 \times - 2 = 6$

2. The given function is

$f(x) = \frac{1}{3} x$

When x=3,

$f(3) = \frac{1}{3} \times 3 = 1$

Similarly,

$f( - 3) = \frac{1}{3} \times - 3 = - 1$

$f(300) = \frac{1}{3} \times 300 = 100$

$f( - 180) = \frac{1}{3} \times - 180 = - 60$

$f(99) = \frac{1}{3} \times 99 = 33$

8 0

3 years ago

Which equations could be used to solve for the

Nana76 [90]

Answer: A,E

Explanation: i just sacrificed my answer to find the right answer

3 0

3 years ago

Tyrianne next solved a quadratic equation her work shown below in which step did Tyrianne make an error 1/2(x+4)^2-3=29

Alisiya [41]

Answer:

step 2

Step-by-step explanation:

3 0

4 years ago