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Mama L [17]
3 years ago
13

Solve for the given length:

Mathematics
1 answer:
Lesechka [4]3 years ago
6 0
Let x= width
Then x+3= length
So 2x+2x+6=26
4x+20
x=5
Width is x=5m and length is x+3=8m
Area is (lenght)(width) so (5)(8)= 40m squared
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Find the perimeter of a rectangle whose length is 3 cm greater than its height, and whose area is 40 cm².
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Step-by-step explanation:

The perimeter of a rectangle can be calcualated with this formula:

P=2l+2h

Where "l" is the lenght and "h" is the height.

 The area of a rectangle can be found with this formula:

A=lh

Where "l" is the lenght and "h" is the height.

In this case we know that:

A=40\ cm^2

Therfore, we can susbsitute them into A=lh and solve for "h" in  order to find its value:

40=(h+3)h\\\\40=h^2+3h\\\\h^2+3h-40=0

Find two number whose sum is 3 and whose product is -40. These are -5 and 8. Then, factorizing, we get:

(h-5)(h+8)=0\\\\h_1=5\\\\h_2=-8

The positive value is the height. Then:

h=5\ cm

Since the length is 3 centimeters greater than its height, we get that this is: Then:

l=5\ cm+3\ cm\\\\l=8\ cm

Substituting values into P=2l+2h, we get that the perimeter is:

P=2(8\ cm)+2(5\ cm)\\\\P=26\ cm

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