Answer:
Kara incorrectly factored 2(16x^2 + 24x + 9) she did not find the correct factors when she factored out. The correct factored expression would be 2(4x+3)^2
Step-by-step explanation:
32x^2 + 48x + 18
2(16x^2 + 24x + 9)
2(16x^2 + 12x) (12x + 9)
2 4x(4x + 3) 3(4x + 3)
2(4x + 3)(4x + 3)
2(4x + 3)^2
Answer:
There is a vertical asymptote at x = 0
Step-by-step explanation:
Answer:
i think is 20 0r 22
Step-by-step explanation:
After 10 hours the snow would be 8 inches deep because 4/5x10 = 8
Answer:
84.13% probability a particular tire of this brand will last longer than 57,100 miles
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

What is the probability a particular tire of this brand will last longer than 57,100 miles
This is 1 subtracted by the pvalue of Z when X = 57100. So



has a pvalue of 0.1587
1 - 0.1587 = 0.8413
84.13% probability a particular tire of this brand will last longer than 57,100 miles