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3 years ago

Solve for the given length:

1 answer:

6 0

Let x= width
Then x+3= length
So 2x+2x+6=26
4x+20
x=5
Width is x=5m and length is x+3=8m
Area is (lenght)(width) so (5)(8)= 40m squared

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Hope someone can help me

Advocard [28]

Hi!

Let's find out how much he has to pay for each of the deals.

Deal 1

£1.75 per mile.

192 x 1.75 = 336

£336

Deal 2

15% off of £680

$\frac{x}{680} \frac{15}{100}$

680 x 15 = 10200

10200/100 = 102

680 - 102 = 578

£578

Deal 3

£90 per day - 1/10

90 x 7 = 630

1/10 of 630 = 63

630 - 63 = 567

£567

The cheapest deal would be Deal 1

Hope this helps! :)

-Peredhel

5 0

3 years ago

Solve the following quadratic inequality 2x^2+3x-5>0

madreJ [45]

Answer:

x < -2.5 and x > 1

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Determine the factors of x2 − 12x − 20.

FrozenT [24]

Answer:

Step-by-step explanation:

Synthetic division is one way to determine whether or not a given number is a root of the quadratic. x^2 − 12x − 20 can be rewritten as x^2 - 12x + 36 - 36 - 20, or (x - 6)^2 - 56, which does not have integer solutions:

(x - 6)^2 - 56 = 0 becomes (x - 6)^2 = 56, which works out to x - 6 = ± 2√14.

None of the possible roots suggested in this problem turns out to be an actual root.

correct response: PRIME

3 0

3 years ago

The electric-vehicle manufacturing company Tesla estimates that a driver who commutes miles per day in a Model S will require a

saul85 [17]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

Please find the complete question in the attached file.

In this question, we assume that "x" denotes as an actual time of the battery charging, that is a uniform random variable that $x \sim U(90, 120)$

In point a:

so, pdf of x =

$\to f(x)= \frac{1}{120-90} = \frac{1}{30} \\\\\to 90 < x$

In point b:

To find

$\to P(x$

In point c:

$\to P(x$

In point d:

$\to P(95< x< 110)$

$= \int^{110}_{95} \frac{1}{30} \ dx\\\\= \frac{110-95}{30} \\\\= \frac{15}{30} \\\\= \frac{1}{2}$

6 0

3 years ago

the longest side of an acute isosceles triangle 8 centimeters . Round to the nearest tenth, what is the smallest possible length

Triss [41]

Let x be the <span>length of each of two congruent sides.

</span>The triangle will be аcute if:
x² + x² > 8²
2x² > 64
x² > 32
x > √32
x > 5.657

So, the smallest possible length of one of two congruent sides have to be 5.7 cm (<span>to the nearest tenth)</span>

7 0

3 years ago

Read 2 more answers