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Pavel [41]
2 years ago
5

Highest to lowest -0.6,0.38, -0.09, 0.7

Mathematics
2 answers:
Olegator [25]2 years ago
4 0

Answer:

0.7, 0.38, -0.6, and -0.09

Step-by-step explanation:

algol132 years ago
3 0

Hey there!

Guide:

• NEGATIVES are BELOW zero

• POSITIVES are ABOVE zero

• DECIMALS are BELOW zero

Highest to lowest: –0.6, 0.38, –0.09, 0.7

0.7 ⬅️ HIGHEST

0.38 ⬅️ 2nd HIGHEST

–0.09 3rd HIGHEST ⬅️

–0.6 ⬅️ LOWEST

Answer: 0.7 , 0.38, –0.09, and –0.6 ☑️

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

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a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l
GrogVix [38]

Answer:

\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}

Step-by-step explanation:

The equation of a line:

y=mx+b

We have

m=\dfrac{2}{3}

substitute:

y=\dfrac{2}{3}x+b

The formula of a distance between a point and a line:

General form of a line:

Ax+By+C=0

Point:

(x_0,\ y_0)

Distance:

d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}

Convert the equation:

y=\dfrac{2}{3}x+b     |<em>subtract y from both sides</em>

\dfrac{2}{3}x-y+b=0    |<em>multiply both sides by 3</em>

2x-3y+3b=0\to A=2,\ B=-3,\ C=3b

Coordinates of the point:

(0,\ 0)\to x_0=0,\ y_0=0

substitute:

d=4

4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}

4=\dfrac{|3b|}{\sqrt{13}}\qquad|    |<em>multiply both sides by \sqrt{13}</em>

4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}   |<em>divide both  sides by 3</em>

b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}

Finally:

y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}

4 0
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3 years ago
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