Item 12 a regular triangular pyramid has a base and lateral faces that are congruent equilateral triangles. it has a lateral sur
face area of 57 square centimeters. what is the surface area of the regular triangular pyramid?
2 answers:
Answer:
76
Step-by-step explanation:
im short on time sorry for no explanation.
Let SA =surface area, la=lateral area, b=base, h=height, l=slant height;
b=l
57=3(1/2b²)
57/3*2=b²
b= √38
SA= 1/2 (√38)²+57 cm²= 94 cm²
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