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3 years ago

12 Times 12 = 144 right?

Mathematics

1 answer:

REY [17]3 years ago

5 0

Answer:

yes it is u are correct

Step-by-step explanation: plz mark brainliest

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If f(x) = 2x - 6 and g(x) = 3x + 9, find (f+g)(x)

valina [46]

Answer:

(f+g)(x) = 5x + 3

Step-by-step explanation:

f(x) = 2x - 6 and g(x) = 3x + 9, find (f+g)(x)

(f+g)(x) = f + g = (2x - 6) + (3x + 9) = 5x + 3

(f+g)(x) = f + g = 5x + 3

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What is the midpoint between (3,5) and (7,9)

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Your anbswer is gonna be 5,7

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If y=8 when x=4 find y when x=5

djyliett [7]

Answer:

y = 10 when x = 5

Step-by-step explanation:

When x = 4, y = 8

Simplify. Divide 4 from both x and y

x = 4/4 = 1

y = 8/4 = 2

when x = 1, y = 2

Next, solve for when x = 5. Mutliply 5 to both x and y

x = 1 * 5 = 5

y = 2 * 5 = 10

y = 10 when x = 5

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Don’t worry about number 7 just 5 and thank you

oksian1 [2.3K]

Subtract 15 from both sides

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3 years ago

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Dwayne drove 18 miles to the airport to pick up his father and then returned home. On the return trip he was able to drive an av

Nesterboy [21]

Answer:

30 mph

Step-by-step explanation:

Let d = distance (in miles)

Let t = time (in hours)

Let v = average speed driving <u>to</u> the airport (in mph)

⇒ v + 15 = average speed driving <u>from</u> the airport (in mph)

Using: distance = speed x time

$\implies t=\dfrac{d}{v}$

Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:

$\implies t=\dfrac{18}{v} \ \ \textsf{and} \ \ t=\dfrac{18}{v+15}$

We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:

$\implies \dfrac{18}{v} +\dfrac{18}{v+15}=1$

Now all we have to do is solve the equation for v:

$\implies \dfrac{18(v+15)}{v(v+15)} +\dfrac{18v}{v(v+15)}=1$

$\implies \dfrac{18(v+15)+18v}{v(v+15)}=1$

$\implies 18(v+15)+18v=v(v+15)$

$\implies 18v+270+18v=v^2+15v$

$\implies v^2-21v-270=0$

$\implies (v-30)(v+9)=0$

$\implies v=30, v=-9$

As v is positive, v = 30 only

So the average speed driving to the airport was 30 mph

(and the average speed driving from the airport was 45 mph)

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2 years ago

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