If f (x) = StartRoot x minus 3 EndRoot, which inequality can be used to find the domain of f(x)? Options Below

Mathematics

2 answers:

Aleksandr [31]4 years ago

8 0

The inequality $x-3 \geq 0$ can be used to find the domain of $f(x)=\sqrt{x-3}$

Answer: Option B

Step-by-step explanation:

We have $f(x)=\sqrt{x-3}$ , domain is the set of all possible x-values which will make the function "work", and will output real y-values. Basically to find domain of any function means to find range of values of x that will give real values of y.

For the equation $f(x)=\sqrt{x-3}$ , we know that there's no value ( iota or complex numbers are there but here we will deal with real numbers ) of negative numbers under square root

∴ ${(} x-3 {)}$ must be greater than or equal to 0.

⇒ $x-3 \geq 0$

umka2103 [35]4 years ago

6 0

Answer:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The easiest common denominator to find is the product of the denominators you have.

The difference is ...

$\dfrac{5}{6}-\dfrac{1}{8}=\dfrac{5}{6}\cdot\dfrac{8}{8}-\dfrac{1}{8}\cdot\dfrac{6}{6}\\\\=\dfrac{40-6}{48}=\boxed{\dfrac{34}{48}}$

Additional comment

The difference numerator and denominator have a common factor of 2, so can be reduced to 17/24. The denominator 24 could have been used as the common denominator from the start.

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Using the least common denominator does not always result in a reduced sum or difference. If some other denominator is used (as here), then you can be assured that the result will need to be reduced to get to lowest terms.

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answer:

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explanation:

given ratio: 12 : 30

divide by 12: