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12345 [234]
3 years ago
12

If f (x) = StartRoot x minus 3 EndRoot, which inequality can be used to find the domain of f(x)? Options Below

Mathematics
2 answers:
Aleksandr [31]3 years ago
8 0

The inequality x-3 \geq 0  can be used to find the domain of f(x)=\sqrt{x-3}

Answer: Option B

<u>Step-by-step explanation:</u>

We have f(x)=\sqrt{x-3}, domain is the set of all possible x-values which will make the function "work", and will output real y-values. Basically to find domain of any function means to find range of values of x that will give real values of y.

For the equation  f(x)=\sqrt{x-3} , we know that there's no value  ( iota or complex numbers are there but here we will deal with real numbers ) of negative numbers under square root  

∴{(} x-3 {)} must be greater than or equal to 0.

⇒ x-3 \geq 0

umka2103 [35]3 years ago
6 0

Answer:

B

Step-by-step explanation:

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You multiply 4 by 2 which gives you 8 and write the equation5+x^{2} =8 then you subtract 5 from 8 to get 3 for the x coordinate.

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To check use the midpoint formula with coordinates D and your endpoint coordinates\frac{5+3}{2}=\frac{8}{2} =4 \\  \frac{-6+12}{2} =\frac{6}{2} =3 and you get the answer for the midpoint which is (4,3)

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