Question

If f (x) = StartRoot x minus 3 EndRoot, which inequality can be used to find the domain of f(x)? Options Below

Answer 1

The inequality $x-3 \geq 0$  can be used to find the domain of $f(x)=\sqrt{x-3}$

Answer: Option B

Step-by-step explanation:

We have $f(x)=\sqrt{x-3}$, domain is the set of all possible x-values which will make the function "work", and will output real y-values. Basically to find domain of any function means to find range of values of x that will give real values of y.

For the equation  $f(x)=\sqrt{x-3}$ , we know that there's no value  ( iota or complex numbers are there but here we will deal with real numbers ) of negative numbers under square root  

∴${(} x-3 {)}$ must be greater than or equal to 0.

⇒ $x-3 \geq 0$

Answer 2

Answer:

B

Step-by-step explanation: