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12345 [234]
4 years ago
12

If f (x) = StartRoot x minus 3 EndRoot, which inequality can be used to find the domain of f(x)? Options Below

Mathematics
2 answers:
Aleksandr [31]4 years ago
8 0

The inequality x-3 \geq 0  can be used to find the domain of f(x)=\sqrt{x-3}

Answer: Option B

<u>Step-by-step explanation:</u>

We have f(x)=\sqrt{x-3}, domain is the set of all possible x-values which will make the function "work", and will output real y-values. Basically to find domain of any function means to find range of values of x that will give real values of y.

For the equation  f(x)=\sqrt{x-3} , we know that there's no value  ( iota or complex numbers are there but here we will deal with real numbers ) of negative numbers under square root  

∴{(} x-3 {)} must be greater than or equal to 0.

⇒ x-3 \geq 0

umka2103 [35]4 years ago
6 0

Answer:

B

Step-by-step explanation:

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The zeros of a quadratic function are 6 and -4. Which of these choices could be the function?
geniusboy [140]

Answer:

C

Step-by-step explanation:

If x = a is a zero of f(x) then (x - a) is a factor of f(x)

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6 0
3 years ago
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Find the total surface area of this triangular prism.<br> 21 cm<br> 29 cm<br> 22 cm<br> 20 cm
mixer [17]

Answer:

313

Step-by-step explanation:

First of all you need to find out the surface of the front.

So you need to do 29cm + 29cm = 58cm.

You then have to do 22cm + 22cm = 44cm

So if you add those two numbers up you will get the front surface which is 102cm.

Next, you need to find the surface of the side.

So you need to do 20cm + 21cm = 41cm

After that, you need to find the back surface.

So you need to add 22cm +22cm = 44cm

Then you have to do 21cm + 21cm = 42cm

Add those two together to get 86cm

Then, you need to do the bottom of the shape.

So you need to add 22cm + 22cm (again) = 44cm

You then need to do 20cm + 20cm = 40cm

Add those together to get 84cm

Finally, you need to add 84cm + 86cm + 102cm + 41cm = 313cm

So your answer is:

Surface: 313

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2 years ago
.......................................
nydimaria [60]
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3 years ago
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