If f (x) = StartRoot x minus 3 EndRoot, which inequality can be used to find the domain of f(x)? Options Below

Mathematics

2 answers:

Aleksandr [31]3 years ago

8 0

The inequality $x-3 \geq 0$ can be used to find the domain of $f(x)=\sqrt{x-3}$

Answer: Option B

<u>Step-by-step explanation:</u>

We have $f(x)=\sqrt{x-3}$ , domain is the set of all possible x-values which will make the function "work", and will output real y-values. Basically to find domain of any function means to find range of values of x that will give real values of y.

For the equation $f(x)=\sqrt{x-3}$ , we know that there's no value ( iota or complex numbers are there but here we will deal with real numbers ) of negative numbers under square root

∴ ${(} x-3 {)}$ must be greater than or equal to 0.

⇒ $x-3 \geq 0$

umka2103 [35]3 years ago

6 0

Answer:

Step-by-step explanation:

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Answer:

y = cot(x - ⅓π) + 2

Step-by-step explanation:

The general equation for a cotangent function with the given properties is

y = Acot(Bx + C) + D, where

A = the stretching factor

π/|B| = the period

C = the phase shift (negative is to the right)

D = the vertical shift

A = 1

π/|B| = π, so1/|B| = 1 and B = 1

C = -⅓π

D = 2

The function is

y = cot(x - ⅓π) + 2

The figure below shows the graph of the function with the given parameters.

Note that the parent function y = cot(x) has the y-axis as an asymptote, so we can measure the phase shift by the movement of the asymptote π units to the right.