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Yuliya22 [10]
3 years ago
12

Assume that a varies directly as b. What is the constant of proportionality if a = 8 when b = 2?

Mathematics
2 answers:
Lena [83]3 years ago
8 0

Answer:

k = 4

Step-by-step explanation:

Given that a varies directly as b then the equation relating them is

a = kb ← k is the constant of variation

To find k use the condition a = 8 when b = 2

k = \frac{a}{b} = \frac{8}{2} = 4

lisov135 [29]3 years ago
8 0

Answer:

K = 4

Step-by-step explanation:

Given that varies a directly as b then the equation relating them is

Simply implies that a is directly proportional to b, that is increase in a will cause increase in, and decrease in a will cause decrease in b, and vice versa, where k remains constant.

a α b

a = kb, where k is constant

To find k use the condition a = 8 when b = 2, we make k the subject of the formular

K = a/b

K = 8/2

K = 4

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Step-by-step explanation:

We can use pythagoreans theorem to solve this

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Where a and b are two sides, and c is the hypotenuse (the side opposite of the right angle)

In this triangle, 7 is the side, and 14 is the hypotenuse.

I will plug in the values into pythagoreans theorem, and then simplify:

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3 years ago
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2 years ago
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n200080 [17]

Answer:

Step-by-step explanation:

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Solve both by elimination can someone help?<br> 2x-5y=-9 , 4x+5y=12<br><br> 3x-2y=12 , 7x-5y=17
lyudmila [28]

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