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3 years ago

Assume that a varies directly as b. What is the constant of proportionality if a = 8 when b = 2?

Mathematics

2 answers:

Lena [83]3 years ago

8 0

Answer:

k = 4

Step-by-step explanation:

Given that a varies directly as b then the equation relating them is

a = kb ← k is the constant of variation

To find k use the condition a = 8 when b = 2

k = $\frac{a}{b}$ = $\frac{8}{2}$ = 4

lisov135 [29]3 years ago

8 0

Answer:

K = 4

Step-by-step explanation:

Given that varies a directly as b then the equation relating them is

Simply implies that a is directly proportional to b, that is increase in a will cause increase in, and decrease in a will cause decrease in b, and vice versa, where k remains constant.

a α b

a = kb, where k is constant

To find k use the condition a = 8 when b = 2, we make k the subject of the formular

K = a/b

K = 8/2

K = 4

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A weather forecaster says the temperature will be about-5C “give or take” 10 degrees. What is the greatest possible temperature?

IRINA_888 [86]

The greatest possible temperature is $5^{\circ} \mathrm{C}$ and least possible temperature is $-15^{\circ} \mathrm{C}$

Solution:

Given that according to weather forecaster the temperature will be about -5 degree celsius given or take 10 degree”

Need to determine greatest possible temperature and least possible temperature.

Give and take in given statement means a temperature can go up by 10 degrees and can go down by 10 degrees

So greatest possible temperature will be $-5^{\circ} \mathrm{C}+10^{\circ} \mathrm{C}=5^{\circ} \mathrm{C}$

Least possible temperature will be $-5^{\circ} \mathrm{C}-10^{\circ} \mathrm{C}=-15^{\circ} \mathrm{C}$

Hence according to weather forecaster, greatest possible temperature = $5^{\circ} \mathrm{C}$ and least possible temperature = $-15^{\circ} \mathrm{C}$

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3 years ago

Dwayne drove 18 miles to the airport to pick up his father and then returned home. On the return trip he was able to drive an av

Nesterboy [21]

Answer:

30 mph

Step-by-step explanation:

Let d = distance (in miles)

Let t = time (in hours)

Let v = average speed driving to the airport (in mph)

⇒ v + 15 = average speed driving from the airport (in mph)

Using: distance = speed x time