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3 years ago

What is the vertex of the function y=|x+3| - 2?

Mathematics

2 answers:

dmitriy555 [2]3 years ago

8 0

Answer:#3

Step-by-step explanation: The vertex form of this equation is y= | x-a | + b. So -(-x) would equal x. In the third answer choice, the x coordinate would be represented by a negative 3 (because two negatives make a positive). The y coordinate would be -2 because N + (-2) = N - 2, thus giving the answer of (-3,-2)

I hope this helped!!

mylen [45]3 years ago

4 0

Answer:

3. (-3,-2)

Step-by-step explanation:

For an absolute value the equation, the transformations are as shown:

y= ±a|b(x-h)|+k.

'h' and 'k' are the vertex coordinates, meaning if y= |x+3|-2:

h= -3

and k= -2

Therefore, we get:

(-3,-2)

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In the diagram, which angles are vertical angles? Select two

lakkis [162]

Answer:

∠ABE and ∠CBD

∠ABC and ∠EBD

Step-by-step explanation:

we know that

<u>Vertical angle</u>s are a pair of opposite and congruent angles formed by intersecting lines

In this problem we have that

∠ABE=∠CBD ------> by vertical angles

∠ABC=∠EBD ------> by vertical angles

therefore

The angles that are vertical angles are

∠ABE and ∠CBD

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8 0

3 years ago

Read 2 more answers

Consider the quadratic function f(x) = x2 – 5x + 12. Which statements are true about the function and its graph? Select three op

lutik1710 [3]

The statement that is true about the quadratic function is (b) the graph of the function is a parabola.

<h3>How to determine the true statements?</h3>

The quadratic function is given as

f(x) = x2 – 5x + 12

Rewrite as

f(x) = x² – 5x + 12

All quadratic functions are parabola

This means that option (b) is true

Set x = -10 to calculate f(-10)

So, we have

f(-10) = (-10)² – 5(-10) + 12

Evaluate

f(-10) = 162

This means that option (a) is false

Set x = 20 to calculate f(20)

So, we have

f(20) = (20)² – 5(20) + 12

Evaluate

f(20) = 312

This means that option (d) is false

Set x = 0 to calculate f(0)

So, we have

f(0) = (0)² – 5(2) + 12

Evaluate

f(0) = 12

This means that option (e) is false

The leading coefficient in f(x) = x² – 5x + 12 is positive

Graphs with positive leading coefficient opens up

This means that option (c) is false

Hence, the true statement about the quadratic function is (b)

Read more about quadratic functions at

brainly.com/question/1214333

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5 0

1 year ago

Please help?

Mazyrski [523]

Answer:

$23\sqrt{3}\ un^2$

Step-by-step explanation:

Connect points I and K, K and M, M and I.

1. Find the area of triangles IJK, KLM and MNI:

$A_{\triangle IJK}=\dfrac{1}{2}\cdot IJ\cdot JK\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 2\cdot 3\cdot \dfrac{\sqrt{3}}{2}=\dfrac{3\sqrt{3}}{2}\ un^2\\ \\ \\A_{\triangle KLM}=\dfrac{1}{2}\cdot KL\cdot LM\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 8\cdot 2\cdot \dfrac{\sqrt{3}}{2}=4\sqrt{3}\ un^2\\ \\ \\A_{\triangle MNI}=\dfrac{1}{2}\cdot MN\cdot NI\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 3\cdot 8\cdot \dfrac{\sqrt{3}}{2}=6\sqrt{3}\ un^2\\ \\ \\$

2. Note that

$A_{\triangle IJK}=A_{\triangle IAK}=\dfrac{3\sqrt{3}}{2}\ un^2 \\ \\ \\A_{\triangle KLM}=A_{\triangle KAM}=4\sqrt{3}\ un^2 \\ \\ \\A_{\triangle MNI}=A_{\triangle MAI}=6\sqrt{3}\ un^2$