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kolezko [41]
3 years ago
7

a man buys a dozen cameras for $1800. He sells them at a profit of $36 each. Express his profit as a percentage of his selling p

rice. ​
Mathematics
1 answer:
Helga [31]3 years ago
6 0

First of all, we need to deduce the price of a single camera:

\dfrac{1800}{12}=150

Now, we know that he profits 36 dollars from each camera. So, we are asking: which percentage of 150 is 36? We have

36 = 150\cdot\dfrac{x}{100}

This equation literally says: 36 is x-percent of 150. And we need to solve for x:

x=\dfrac{36\cdot 100}{150} =24

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Using the monthly payments formula, it is found that a car with a value of at most $25,293.

<h3>What is the monthly payment formula?</h3>

It is given by:

A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}

In which:

  • P is the initial amount.
  • r is the interest rate.
  • n is the number of payments.

In this problem, we have that the parameters are given as follows:

A = 400, n = 70, r = 0.035.

Hence:

r/12 = 0.035/12 = 0.002917.

Then we have to solve for P to find the maximum value of the car.

A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}

400 = P\frac{0.002917(1.002917)^{70}}{(1.002917)^{70}-1}

P = \frac{400[(1.002917)^{70}-1]}{0.002917(1.002917)^{70}}

P = $25,293.

More can be learned about the monthly payments formula at brainly.com/question/26267630

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