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mash [69]
2 years ago
13

A copy machine makes

Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
4 0
\bf \begin{array}{ccllll}
copies&minutes\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
36&1\\
189&x
\end{array}\implies \cfrac{36}{189}=\cfrac{1}{x}

solve for "x"
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JNZ~ KOA. Find the unknown measures
shepuryov [24]

Answer:

<h2>x = 8.5in, y = 17in, r = 28°, s = 62°</h2>

Step-by-step explanation:

If ΔJNZ and ΔKOA are similar, then corresponding sides are in proportion and corresponding angles are congruent.

We have the proportion:

\dfrac{JN}{KO}=\dfrac{NZ}{OA}=\dfrac{ZJ}{AK}

and equations:

m\angle N=m\angle O=90^o\\m\angle Z=m\angle A=28^o\\m\angle J=m\angle K=62^o

We have:

JN=8\ in,\ NZ=15\ in,\ KO=4\ in,\ AK=x\ in,\ ZJ=y\ in

For y we must use the Pythagorean theorem:

ZJ^2=JN^2+NZ^2\\\\y^2=8^2+15^2\\\\y^2=64+225\\\\y^2=289\to y=\sqrt{289}\\\\y=17\ in

\dfrac{JN}{KO}=\dfrac{ZJ}{AK}\to\dfrac{8}{4}=\dfrac{17}{x}        <em>cross multiply</em>

8x=(4)(17)

8x=68          <em>divide both sides by 8</em>

x=8.5\ in

4 0
2 years ago
Read 2 more answers
There are 6 pencils in the drawer Sally placed 4 more pencils in the drawer how many pencils are now there in all
Lina20 [59]

Answer:

10

Step-by-step explanation:

6+4=10

4 0
3 years ago
Read 2 more answers
How to work this out ?
Free_Kalibri [48]

Answer:

The solution is (-3, -2).

Step-by-step explanation:

Please note that if you simply add these 2 equations together, 9x - 9x = 0, and you are then left with -5y = 10.  Thus, y = -2.  Subbing -2 for y in the first equation, we get 9x - 8(-2) = -11, or 9x + 16 = -11.

Subtracting 16 from both sides, we get 9x = -27, so that x = -3.

The solution is (-3, -2).


6 0
2 years ago
M is the midpoint of QR<br><br> M = (-2,6)<br> Q= (8,-10)<br> R = ????
Zolol [24]

Answer:

R = (-12, 22)

Step-by-step explanation:

Unfortunately it's not a straight line, so gonna need to put in some extra work. Basically think of it like breaking it into it's horizontal and vertical components then doubling them.

From Q to M you move 10 spaces to the left, so to go from M to R you will go another 10 to the left.  Similarly, you start at -10 for the y value and go up 16 to 6, and you  will need to go up another 16 to get to R.

So for x, 8 -10 = -2 then -2 - 10 = -12, so R's x value is -12

y we do the same thing.  Gonna do it in one step though.  -10 + 16 + 16 = 22

So R is (-12, 22)

4 0
3 years ago
1+secA/sec A = sin^2 A / 1-cos A​
Fofino [41]

Answer:  see proof below

<u>Step-by-step explanation:</u>

\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

<u>Proof LHS → RHS</u>

\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}

\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}

\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}

\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}

\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}

\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark

3 0
3 years ago
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