All categories

3 years ago

Need an answer fast

Mathematics

1 answer:

natka813 [3]3 years ago

5 0

Answer:

What do you need help with?

You might be interested in

Help please , im confused

Neporo4naja [7]

Answer:

Step-by-step explanation:

There is nothing I can solve

5 0

3 years ago

What are the lengths of line segments AB and BC

jasenka [17]

I need more information

4 0

3 years ago

In 2018, the population will grow over 700,000.The population of a city in 2010 was 450,000 and was growing at a rate of 5% per

Firlakuza [10]

Answer:

The year is 2020.

Step-by-step explanation:

Let the number of years passed since 2010 to reach population more than 7000000 be 'x'.

Given:

Initial population is, $P_0=450,000$

Growth rate is, $r=5\%=0.05$

Final population is, $P=700,000$

A population growth is an exponential growth and is modeled by the following function:

$P=P_0(1+r)^x$

Taking log on both sides, we get:

$\log(P)=\log(P_0(1+r)^x)\\\log P=\log P_0+x\log (1+r)\\x\log (1+r)=\log P-\log P_0\\x\log(1+r)=\log(\frac{P}{P_0})\\x=\frac{\log(\frac{P}{P_0})}{\log(1+r)}$

Plug in all the given values and solve for 'x'.

$x=\frac{\log(\frac{700,000}{450,000})}{\log(1+0.05)}\\x=\frac{0.192}{0.021}=9.13\approx 10$

So, for $x > 9.13$ , the population is over 700,000. Therefore, from the tenth year after 2010, the population will be over 700,000.

Therefore, the tenth year after 2010 is 2020.

8 0

3 years ago

What is 1/4 of 76 in a mathequ on

Softa [21]

The answer is 19. You have to do 1/4 x 76/1 which is basically 76 divided by 4, which gives you 19.

4 0

3 years ago

Simplest way to multi-step equations...

Bess [88]

Answer: calculator boi

Step-by-step explanation:

4 0

3 years ago

Need an answer fast​

Need an answer fast