All categories

3 years ago

Negative 15=negative 0.2x

Mathematics

1 answer:

Ray Of Light [21]3 years ago

3 0

If -15 is equal to -0.2x, then 15/0.2=75
x=75

You might be interested in

Hey can you please help me posted picture of question

MArishka [77]

It would be letter D - 3648.

The probability of winning is 0.76 and the probability of losing is 0.24.

In each simulation the probability of winning exactly one match is: P(win one match) = 2C1 x 0.76 x 0.24 = 0.3648

Multiply the result by 10,000 simulations to get the expected number of times that exactly one match is won.
10,000 x 0.3648 = 3648 times.

4 0

4 years ago

What system of equations is shown on the graph below?

asambeis [7]

The answer is optio A.

6 0

3 years ago

Choose the correct product of (2x + 10)^2

wlad13 [49]

(2x+10)(2x+10) use FOIL to solve (First, Outer, Inner, Last)
4x^2+20x+20x+100
Combine like terms
4x^2+40x+100

3 0

3 years ago

Read 2 more answers

Barb is making a bead necklace.She strings 1 white bead,then 3 blue beads,then 1 white bead,and so on.Write the numbers for the

blondinia [14]

1 then 3 1 then three so 1+3+1+3+1+3+1+3

8 0

3 years ago

Find the volume of the region between the planes x plus y plus 2 z equals 2 and 4 x plus 4 y plus z equals 8 in the first octant

Alex787 [66]

Find the intercepts for both planes.

Plane 1, x + y + 2z = 2:

$y=z=0\implies x=2\implies (2,0,0)$

$x=z=0\implies y=2\implies(0,2,0)$

$x=y=0\implies 2z=2\implies z=1\implies(0,0,1)$

Plane 2, 4x + 4y + z = 8:

$y=z=0\implies4x=8\implies x=2\implies(2,0,0)$

$x=z=0\implies4y=8\impliesy=2\implies(0,2,0)$

$x=y=0\implies z=8\implies(0,0,8)$

Both planes share the same x- and y-intercepts, but the second plane's z-intercept is higher, so Plane 2 acts as the roof of the bounded region.

Meanwhile, in the (x, y)-plane where z = 0, we see the bounded region projects down to the triangle in the first quadrant with legs x = 0, y = 0, and x + y = 2, or y = 2 - x.

So the volume of the region is

$\displaystyle\int_0^2\int_0^{2-x}\int_{\frac{2-x-y}2}^{8-4x-4y}\mathrm dz\,\mathrm dy\,\mathrm dx=\displaystyle\int_0^2\int_0^{2-x}\left(8-4x-4y-\frac{2-x-y}2\right)\,\mathrm dy\,\mathrm dx$

$=\displaystyle\int_0^2\int_0^{2-x}\left(7-\frac72(x+y)\right)\,\mathrm dy\,\mathrm dx=\int_0^2\left(7(2-x)-\frac72x(2-x)-\frac74(2-x)^2\right)\,\mathrm dx$

$=\displaystyle\int_0^2\left(7-7x+\frac74 x^2\right)\,\mathrm dx=\boxed{\frac{14}3}$

3 0

3 years ago