9514 1404 393
Answer:
y = 0
Step-by-step explanation:
Subtracting the right side gives ...

The factor multiplying y cannot be zero, so y must be zero.
Using derivatives, it is found that the best estimate of f '(2) based on this table of values is of 10.
The rate of change <u>from x = 0 to x = 2</u> is given by:

From <u>x = 2 to x = 4</u>, it is given by:

The average of these rates is:

Hence, the best estimate of f '(2) based on this table of values is of 10.
To learn more about derivatives, brainly.com/question/18590720
Answer:
Blue, if you look, they both are close, but due to the pathagrium theory blue is longer.
Step-by-step explanation:
Answer:
y = 2.1x +5, 21 miles
Step-by-step explanation:
We will denote miles as "x"
Since she tipped the driver $5, that is a flat rate and that will be our y-intercept. Since it costs $2.10 per mile, we need to multiply that number by the number of miles
So our equation will be y = 2.1x +5
In order to figure out how many miles Ann lives from the airport, we need to substitute y for her grand total that she was charged
This gives us 49.10 = 2.10x + 5
First we need to subtract 5 from each side to get 44.10 = 2.10x
We then need to divide both sides by 2.10 to get 21 = x
Ann drove 21 miles
Answer:
Step-by-step explanation:
Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discharging hot water into the river is given by
T(x) = 160-0.05x^2
a. [0, 10]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
The average temperature
= (160 + 155)/2 = 157.5
b. [10, 40]
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (80 + 155)/2 = 117.5
c. [0, 40]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (160 + 80)/2 = 120