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aliina [53]
4 years ago
7

​one column of a table in a relational database is called a(n) ____.

Computers and Technology
1 answer:
ziro4ka [17]4 years ago
3 0
One column of a table in  relational database is called an attribute(property).
You might be interested in
Word wrap is the same as __________ return and means you let the ______________ control when it will go to a new line.
dusya [7]

Word wrap is the same as; Soft Return

Word wrap means that you let the; Computer Control when it will go to a new line

<h3>What is Text Wrapping?</h3>

Text wrapping is simply defined as a process used in MS Word to Wrap a Text around an Image.

Now, the way it is done is by selecting the image you want to wrap text around and then On the Format tab, click the Wrap Text command in the Arrange group, then select the desired text wrapping option to wrap the text.

Finally Word wrap is also same as using soft return and letting the computer control when it goes to the next line.

Read more about text wrapping at; brainly.com/question/5625271

5 0
2 years ago
Ali is creating a document on a system using his login credentials. His colleague needs to use his system to access documents. H
svp [43]

Answer:I am thinking C

Explanation:

If he can multi-task he could ask his colleague for their computer and then when his colleague is done with his computer he could send the document to his computer and then delete it from his colleagues computer.

8 0
3 years ago
4-Translate the following C program to MIPS assembly program (Please explain each instruction in your code by a comment and subm
earnstyle [38]

Answer:

.data

str1: .asciiz "Hello"

str2: .asciiz "mars"

msg: .asciiz "String after the concatenate: "

.text

main:

#load the address str1 to $a0

la $a0,str1

#initialize $t0 with 0

li $t0,0

#loop to find the length of str1

#$t0 stores the length of str1

loop1:

#load byte of $a0 to $t1

lb $t1,0($a0)

#branch for equal.If $t1 equal to 0,jump to label stop1

beq $t1,0,stop1

addi $t0,$t0,1 #increase the count

addi $a0,$a0,1 #increase the address

#jump to label loop1

j loop1

stop1:

#load the address of str2 to $a1

la $a1,str2

#loop2 concatenate the each element in str2 to str1

loop2:

lb $t2,0($a1) #load character in str2 to $t2

sb $t2,0($a0) #store value in $t2 to str1

beq $t2,0,stop2

addi $a1,$a1,1 #increase the address of str2

addi $a0,$a0,1 #increase the address of str1

j loop2

stop2:

#syscall for print string is $v0 = 4

#syscall to termiante the program is $v0 = 10

#print the message

li $v0, 4

la $a0, msg

syscall

#print the concatenated string

li $v0,4

la $a0,str1

syscall

#termiante the program

li $v0, 10

syscall

Explanation:

3 0
3 years ago
List the components of a typical operating system and summarize the role of each in a single phrase.
yanalaym [24]

Answer:

The answer is below

Explanation:

There are several components of operating systems, this may be based on the specific types of Operating systems. However, here are some of the major components.

1. Kernel: it delivers the primary level of control on all the computer peripherals.

2. Process Execution: it serves as a connection between the hardware and application program

3. Interrupt: it provides a dependable technique for the OS to transmit & respond to their surroundings.

4. Memory Management: it regulates main memory and then moves processes between disk & main memory during implementation.

5. Multitasking: it interprets the activities of many independent computer programs on a similar computer system.

6. Networking: it defines the interaction of processor through communication lines

7. Security: it protects the activities of other processes going in the system

8. User Interface: it provides permission for a computer operator to get the information.

3 0
3 years ago
4.14 LAB: Countdown until matching digits In C++ Write a program that takes in an integer in the range 20-98 as input. The outpu
Fantom [35]

Answer:

Here is the C++ program:

#include <iostream>  // to use input output functions

using namespace std;   // to identify objects like cin cout

int main() { //start of main function

   int number;  //an integer value

   cout<<"Enter an integer: ";  //prompts user to enter a number

   cin >> number;  // reads integer value from user

   if (number > 98 || number < 20) {  //if number is not between 20 and 98

  cout<<"Input must be 20-98";   }  //display this message if number is not between 20 and 98

 else {  // if number is in range 20-98

   while(number%11){  // loop keeps taking mod of input number with 11 until matching digits found

       cout<<number<<" ";  //displays the numbers

       number--;     }  // decrements the value of number by 1

    cout<<number<<" "; }  } // displays the matching digits

Explanation:

I will explain the program with an example:

Let suppose the number = 90

The if condition evaluate to false because 90 is in the range of 20-98 so the else part executes which has a while loop that works as following:

while(number % 11)

At first iteration:

This while(number % 11) is basically equivalent to :

while(number % 11 != 0)

while(90 % 11)

The % operator is the modulo operator which returns the remainder of the division. So when 90 is divided by 11 the remainder is 2. This is not equal to 0. So the statement under while condition executes:

cout<<number<<" "; This statement displays the number on output screen. Since number = 90 so 90 is printed. " " adds a space with the number

90

Next the value of number is decremented to 1 so number = 89

At second iteration:

while(number % 11) becomes:

while(89 % 11)

When 89 is divided by 11 the remainder is 1. This is not equal to 0. So the statement under while condition executes:

cout<<number<<" "; This statement displays the number on output screen. Since number = 89 so 89 is printed. " " adds a space with the number

90 89

Next the value of number is decremented to 1 so number = 88

At third iteration:

while(number % 11) becomes:

while(88 % 11)

When 89 is divided by 11 the remainder is 0. So the while loop breaks because the condition while(number % 11 != 0) evaluates to false. So the statement in while loop does not execute and program control moves to the following statement:

    cout<<number<<" "; This statement displays that number whose digits match on the output screen with a space. So the output of the entire program is:

90 89 88

The program along with the output using example given in the question i.e. input is 93 is attached in a screenshot.

6 0
3 years ago
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