every program you open. Under the File menu, all of the following are the same in every program except
Save
Open
Close
Merge
Answer:
#include <iostream>
#include <cstring>
using namespace std;
bool isAPalindrome(char* palindrome);
int main()
{
char palindrome[30];
bool palindrome_check;
cout << "Please enter an word or phrase.\n";
cin.getline(palindrome, 30);
palindrome_check = isAPalindrome(palindrome);
if (palindrome_check = true)
{
cout << "Input is a palindrome\n";
}
else
{
cout << "Inputis not a palindrome\n;";
}
system("pause");
return 0;
}
bool isAPalindrome(char* palindrome)
{
char* front;
char* rear;
front = palindrome;// starts at the left side of the c string
rear = (palindrome + strlen(palindrome)) - 1;//starts at the right side of the c-string. adds the c string plus the incriment value of s
while (front <= rear)
{
if (front = rear)
{
front++;
rear--;
}
else
{
return false;
}
}
return true;
}
The internet is a vast network that connects computers, cellular devices, and cable together from all over the world. There is wireless internet (Wi-Fi) which doesn’t use lines/cables to connect to devices. Cellular technology provides wireless internet access through cellphones. Finally there is satellite which travels an enormous distance from Earth to a satellite.
Answer:
False
Explanation:
The scheme where you can find the greatest common divisor (GCD) of two integers by repetitive application of the division algorithm is known as Euclidean Algorithm.
The Euclidean Algorithm for calculating GCD of two numbers X and Y can be given as follows:
- If X=0 then GCD(X, Y)=Y since the Greatest Common Divisor of 0 and Y is Y.
- If Y=0 then GCD(X, Y)=X since the Greates Common Divisor of 0 and X is X.
- Let R be the remainder of dividing X by Y assuming X > Y. (R = X % Y)
- Find GCD( Y, R ) because GCD( X, Y ) = GCD(Y, R ).
- Repeat the above steps again till R = 0.
I believe lightbulbs have different brightness because of there quality parts that make it. The cheaper they are usually the worse quality. That is my theory.
