Answer:
f(x)=(x-2)(x+2)(x-5)
Step-by-step explanation:
f(x)=x³-5x²+4x-20 1. Just group randomly
f(x)=x²(x-5)+4(x-5) 2. Factor the groupings
f(x)=(x²+4)(x-5)
<u>f(x)=(x-2)(x+2)(x-5)</u> 3. Factor the difference of two squares
Answer:
A) 68.33%
B) (234, 298)
Step-by-step explanation:
We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:
A. P (250 x < 282)
P ((x1 - m) / sd < x < (x2 - m) / sd)
P ((250 - 266) / 16 < x < (282 - 266) / 16)
P (- 1 < z < 1)
P (z < 1) - P (-1 < z)
If we look in the normal distribution table we have to:
P (-1 < z) = 0.1587
P (z < 1) = 0.8413
replacing
0.8413 - 0.1587 = 0.6833
The percentage of pregnancies last between 250 and 282 days is 68.33%
B. We apply the experimental formula of 68-95-99.7
For middle 95% it is:
(m - 2 * sd, m + 2 * sd)
Thus,
m - 2 * sd <x <m + 2 * sd
we replace
266 - 2 * 16 <x <266 + 2 * 16
234 <x <298
That is, the interval would be (234, 298)
Answer:
In think the answer is 42,000
Step-by-step explanation:
Answer:
A: Neither is a better deal, they cost the same person cubic foot
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B: The large truck's volume is 2.3 times greater than the small truck's
C: At least: three vans, or two small trucks, or one large truck
Step-by-step explanation:
V=Lhw R=$/ft³
Vv=10.5(6)(6)
Vv=378 ft³
Rv=94.5/378
Rv= 25¢ per ft³
Vs=12(8)6.75
Vs=648 ft³
Rs=162/648
Rs=25¢ per ft³
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Vl=20(8.75)8.5
Vl=1487.5 ft³
1487.5=648n
2.295=n
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