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QveST [7]
3 years ago
11

Please helpppppppppp

Mathematics
2 answers:
VikaD [51]3 years ago
4 0

Answer:

A = 6k^2 + 36

Step-by-step explanation:

6k^2 - 36k k^2 + 12k + 36

--------------- × -------------------- = 1

A k^2 - 36

6k ( k - 6) ( k + 6) ( k + 6)

--------------- × --------------------- = 1

A (k - 6) (k +6)

6k ( k + 6)

-------------- = 1

A

When cross multiplied:

A = 6k ( k + 6)

A = 6k^2 + 36

user100 [1]3 years ago
4 0

The answer is a=6k(k+6)

<u>Step-by-step explanation:</u> use Square of Sum (a+b)^2=a^2+2ab+b^2 and use Difference of Squares a^2-b^2=(a+b)(a-b).

\frac{6k^2-36k}{a}*\frac{k^2+12k+36}{k^2-36} =1 factor out the common term 6k

\frac{6k(k-6)}{a}*\frac{k^2+12k+36}{k^2-36}=1\\\\\frac{6k(k-6)}{a}*\frac{k^2+2(k)(6)+6^2}{k^2-36}=1 use Square of Sum then Difference of Squares

\frac{6k(k-6)}{a}+\frac{(k+6)^2}{(k^2-36)} =1\\\\\frac{6k(k-6)}{a}+\frac{(k+6)^2}{(k+6)(k-6)} =1\\\\ cancel k-6 then use the rule a/b*c/d=ac/bd

\frac{6k}{a}*\frac{(k+6)^2}{k+6} =1\\\\\frac{6k(k+6)^2}{a(k+6)} =1\\\\\frac{6k(k+6)}{a}=1\\\\6k(k+a)=a\\\\a=6k(k+6)

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great rest of Black History Month! :-)  

- Cutiepatutie ☺❀❤

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Answer:

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Step-by-step explanation:

1). Height of the trees at Yard Works are = 7,9,7,12,5 feet

So mean height of the trees = (7+9+7+12+5)÷5

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2). In the same way mean height of the trees at Grow Station=(9+11+6+12+7)/5= 45/5 = 9

Now we will calculate the mean deviation of the tress at Grow Station

= ∑║(height of the tree-mean height of the tree)║/(number of trees)

= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)

= (0+2+3+3+2)/5

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Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

                                                             

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