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QveST [7]
3 years ago
11

Please helpppppppppp

Mathematics
2 answers:
VikaD [51]3 years ago
4 0

Answer:

A = 6k^2 + 36

Step-by-step explanation:

6k^2 - 36k k^2 + 12k + 36

--------------- × -------------------- = 1

A k^2 - 36

6k ( k - 6) ( k + 6) ( k + 6)

--------------- × --------------------- = 1

A (k - 6) (k +6)

6k ( k + 6)

-------------- = 1

A

When cross multiplied:

A = 6k ( k + 6)

A = 6k^2 + 36

user100 [1]3 years ago
4 0

The answer is a=6k(k+6)

<u>Step-by-step explanation:</u> use Square of Sum (a+b)^2=a^2+2ab+b^2 and use Difference of Squares a^2-b^2=(a+b)(a-b).

\frac{6k^2-36k}{a}*\frac{k^2+12k+36}{k^2-36} =1 factor out the common term 6k

\frac{6k(k-6)}{a}*\frac{k^2+12k+36}{k^2-36}=1\\\\\frac{6k(k-6)}{a}*\frac{k^2+2(k)(6)+6^2}{k^2-36}=1 use Square of Sum then Difference of Squares

\frac{6k(k-6)}{a}+\frac{(k+6)^2}{(k^2-36)} =1\\\\\frac{6k(k-6)}{a}+\frac{(k+6)^2}{(k+6)(k-6)} =1\\\\ cancel k-6 then use the rule a/b*c/d=ac/bd

\frac{6k}{a}*\frac{(k+6)^2}{k+6} =1\\\\\frac{6k(k+6)^2}{a(k+6)} =1\\\\\frac{6k(k+6)}{a}=1\\\\6k(k+a)=a\\\\a=6k(k+6)

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great rest of Black History Month! :-)  

- Cutiepatutie ☺❀❤

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dolphi86 [110]

Given:

(ax+2)(bx+7)=15x^2+cx+14

And

a+b=8

Required:

To find the two possible values of c.

Explanation:

Consider

\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}

So

\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}

And also given

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Now from (1) and (2), we get

\begin{gathered} a+\frac{15}{a}=8 \\  \\ a^2+15=8a \\  \\ a^2-8a+15=0 \end{gathered}a=3,5

Now put a in (1) we get

\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}

We can interpret that either of a or b are equal to 3 or 5.

When a=3 and b=5, we have

\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}

When a=5 and b=3, we have

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Final Answer:

The option D is correct.

31 and 41

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