If b is in the first position then c can be in any 1 of the remaining 6 positions.
If we start with ab then the letter c can be in any one of 5 positions and if we have aab there are 4 possible positions for c and so on.
So the total number of possible sequences where b comes first = 6+5+4+3+2+1 = 21.
The same argument applies when c comes before b so that gives us 21 ways also.
So the answer is 2 *21 = 42 different sequences.
A more direct way of doing this is to use factorials:-
answer = 7! / 5! = 7 * 6 = 42.
( We divide by 5! because of the 5 a's.)
11 turkeys come into the field. 18 plus 9 is 27. 27 minus 5 is 22. half of 22 is 11.
Answer:
0.1515151515151515
Step-by-step explanation:
Im not sure if you need to find the area or de expression of how to find the AREA. but what you do if explain how you can find it by multiplying that will be 4.. and then also 4? Im not sure but you can try
Step-by-step explanation:
It's an irrational number.
![\sqrt[3]{275:7}=\sqrt[3]{\dfrac{275}{7}}=\dfrac{\sqrt[3]{275}}{\sqrt[3]{7}}=\dfrac{\sqrt[3]{275}\cdot\sqrt[3]{7^2}}{\sqrt[3]{7}\cdot\sqrt[3]{7^2}}=\dfrac{\sqrt[3]{275\cdot49}}{\sqrt[3]{7\cdot7^2}}\\\\=\dfrac{\sqrt[3]{13475}}{\sqrt[3]{7^3}}=\dfrac{\sqrt[3]{13475}}{7}=\dfrac{1}{7}\sqrt[3]{13475}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B275%3A7%7D%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B275%7D%7B7%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B275%7D%7D%7B%5Csqrt%5B3%5D%7B7%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B275%7D%5Ccdot%5Csqrt%5B3%5D%7B7%5E2%7D%7D%7B%5Csqrt%5B3%5D%7B7%7D%5Ccdot%5Csqrt%5B3%5D%7B7%5E2%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B275%5Ccdot49%7D%7D%7B%5Csqrt%5B3%5D%7B7%5Ccdot7%5E2%7D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B13475%7D%7D%7B%5Csqrt%5B3%5D%7B7%5E3%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B13475%7D%7D%7B7%7D%3D%5Cdfrac%7B1%7D%7B7%7D%5Csqrt%5B3%5D%7B13475%7D)
