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2 years ago

Solve (3x – 2)= 49 using the Square Root Property (completing the square).

Mathematics

1 answer:

morpeh [17]2 years ago

3 0

Answer:

(3x-2)=49

(3x-2)=7×7

3x=7×7+2

3x=49+2

3x=51

3x/3=51/3

×=17

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Plz write this on paper help me and send it❤️

vovangra [49]

Answer:

1. $27^{\frac{2}{3} } =9$

2. $\sqrt{36^{3} } =216$

3. $(-243)^{\frac{3}{5} } =-27$

4. $40^{\frac{2}{3}}=4\sqrt[3]{25} =4325$

5. Step 4: $(\frac{343}{27}) ^{-1} =\frac{27}{343}$

6. $D. -72cd^{7}$

Step-by-step explanation:

Use the following properties:

$a^{\frac{x}{y} } =\sqrt[x]{a^{y} }$

$\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}$

$a^{-n} =\frac{1}{a^{n} }$

$(xy)^{z} =x^{z} y^{z} \\\\$

$(x^{y}) ^{z} =x^{yz}$

$x^{y} x^{z} =x^{y+z}$

So:

1. $27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9$

2. $\sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36} \sqrt{36} =6*6*6=216$

3. $(-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27$

4. $40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325$

5. $(\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}$

$(-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}$

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2 years ago

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Answer:

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Step-by-step explanation:

Given that:

Charges of taxi 1 = $3.00 per mile

Charges of taxi 2 = $1.77 per kilometer

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Cost of a 12 miles ride for taxi 1 and taxi 2.

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Let us first convert the charges of each taxi to per mile.

Taxi 1 charges are already given in per mile.

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Charges for 12 miles = 2.85 $\times$ 12 = $34.20

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A 12 mile ride in Taxi 1 costs $36.00, and in Taxi 2 it costs $34.20.

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