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Virty [35]
3 years ago
13

How would you evaluate f(-2) and f(a) for f(x) = 2x^2-x+5

Mathematics
1 answer:
kifflom [539]3 years ago
7 0
\bf f(x)=2x^2-x+5\\\\
-------------------------------\\\\
f(-2)=2(-2)^2-(-2)+5\implies f(-2)=2(-2)(-2)-(-2)+5
\\\\\\
f(-2)=2(4)+2+5\implies f(-2)=8+2+5\implies f(-2)=15
\\\\\\
f(a)=2(a)^2-(a)+5\implies f(a)=2a^2-a+5
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Answer:cosA = \frac{a+2}{2a}

Step-by-step explanation:

Given that the lengths of the sides of a triangle are consecutive integers

Since side cannot be negative we can assume that the sides are

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we get

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3 years ago
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Answer:

$25.08

Step-by-step explanation:

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3 years ago
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3 years ago
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8 0
3 years ago
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Step-by-step explanation:

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<u>Decimal form: 0.6 repeated</u>

<u>Percent form: about 66.67%</u>

4 0
3 years ago
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