Answer:
i dont know why u deleted my answer- but ok
Step-by-step explanation:
The first thing to do is find the slope of the given line m = (y2-y1)/(x2-x1). We need to find the slope because it is required to find the slope of the perpendicular line.
m = (-7-5)/(5+11) = -12/16 = -3/4
Now we find the midpoint of the line, this is where the perpendicular bisector be. Using the Midpoint equation
M=((x1+x2)/2,(y1+y2)/2)
M=((-11+5)/2, (5-7)/2)
M=(-6/2, -2/2)
M=(-3,-1)
Now that we have the slope and midpoint we can find the perpendicular bisector. A line is perpendicular to another if, when you multiply their slopes together they equal -1. To do this we simply invert the numerator and denominator of our current slope and flip the sign from negative to positive.
So, -3/4 becomes positive 4/3 for our new line. So for our perpendicular line we now know two things, the slope and a point on it (the bisector point). To find the equation of the line we need to plug the known point and slope into the equation y = mx + b and solve for b.
-1 = 4/3(-3) + b
-1 = -4 + b
b = -1 + 4
b = 3
Now we can build our equation for our perpendicular line
y = 4/3x + 3
We can find slope by changing this to slope intercepts form. to do that we must isolate y.
subtract 2x from both sides: 3y = -2x + 10
then divide both sides by 3: y = -2/3x + 10/3
slope intercept form follows the formula y = mx + b where m is the slope.
m in this case is -2/3 and that's your slope