To have the same cost at both companies, the number of stickers will have to be 40
Company A :
Design Fee = $30
Costvper sticker = $0.80
Company B :
Design Fee = $14
Cost per sticker = $1.20
Let the number of stickers = p
Total cost of company A = 30 + 0.80p
Total cost of company B = 14 + 1.20p
For the cost to be the same :
Company A = Company B
30 + 0.80p = 14 + 1.20p
Collect like terms :
30 - 14 = 1.20p - 0.80p
16 = 0.40p
Divide both sides by 0.40
p = 16/0.40
p = 40 stickers
Therefore, to have the same price, 40 stickers will have to be ordered.
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Answer:
las respuestas se encuentran en la foto
Step-by-step explanation:
Answer:
17) h=I(1-cosθ); 18) h=1.404.
Step-by-step explanation:
17) h=I-BC;
In ΔABC: m(∠C)=90°, m(∠B)=θ, AB=I, then BC=AB*cos(∠B); ⇒ BC=Icosθ;
Then h=I-Icosθ or h=<u>I(1-cosθ)</u>.
18) if I=6 and θ=40°, then h=6(1-cos40°)≈6*(1-0.766)=<u>1.404</u>, where cos40°≈0.766.
For more details see the attachment.
Hey there!
We can solve systems two ways - substitution and elimination. It seems in this case that elimination is going to be easier.
Let's begin by multiplying the top equation by 3, and the bottom equation by 4:
3(5x - 4y = -24)
15x - 12y = -72
4(4x + 3y = 18)
16x + 12y = 72
Next, we'll add the two equations together to get rid of, or eliminate, the y variable and solve for the x variable:
(15x - 12y = -72) + (16x + 12y = 72)
31x = 0
x = 0
Next, we'll plug the value of the x variable into the top equation and solve for the y variable:
5(0) - 4y = -24
-4y = -24
y = 6
Therefore, x = 0 and y = 6.
Hope this helps!! :)
Answer:
1. 13.23x^2
2. 13.23/x^3
3 . 1.323/x
4.13.23x^12
Step-by-step explanation:
pls mark me brainlest if u can those took forever lol