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olga55 [171]
3 years ago
12

Please help sorry it’s hard to read

Mathematics
2 answers:
lawyer [7]3 years ago
6 0

Answer:6 to 10

Step-by-step explanation:

Lera25 [3.4K]3 years ago
3 0

The equivalent ratios are 3 to 5, 24 to 40, and 6 to 10.

Ratios are equivalent when they can be simplified down to the same ratio, for example 2 to 4 simplifies to 1 to 2 (by dividing by 2), and so does 3 to 6 (by dividing by 3), so these are equivalent. We can find answers by first simplifying the original ratio 12 to 20, which we can do by finding common factors and dividing by them:

12 to 20

÷ 2

6 to 10 (here we have found one answer)

÷ 2

3 to 5 (and here is another answer)

We then get 24 to 40 by multiplying the original ratio by 2, so:

12 to 20

× 2

24 to 40

I hope this helps! Let me know if you have any questions :)

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3 years ago
I need help please ​
Natasha2012 [34]

Answer:

  B.  $2862

Step-by-step explanation:

Using n=5 in the given equation, we get ...

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4 0
4 years ago
Am I correct?<br> will mark brainliest
jeka94

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Step-by-step explanation:

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8 0
3 years ago
Help with some questions please Brainilest answer !/
murzikaleks [220]
Ok , lots of questions=lower standard of explanation
just answers


5. 8.5 times 10^12
6. 0.001260-7,003,000
7.3.843 times 10^4
9. x=1
10. 7^(x+5)=49^(x+3)
11. 1.03
12. 25,700(0.85)^x
13. 10a√a
14. 2 x^{2}  y^{4}  \sqrt[3]{5x^{2}}
15.6√3
16. \frac{2 \sqrt{3x} }{3x}
17. 4 \sqrt[3]{x^{2}}
18.64 x^{ \frac{10}{3} }  y^{ \frac{5}{2} }
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4 0
3 years ago
Read 2 more answers
1)
MrRissso [65]

Answer:

Step-by-step explanation:

The diagram of the triangles are shown in the attached photo.

1) Looking at ∆AOL, to determine AL, we would apply the sine rule

a/SinA = b/SinB = c/SinC

21/Sin25 = AL/Sin 105

21Sin105 = ALSin25

21 × 0.9659 = 0.4226AL

AL = 20.2839/0.4226

AL = 50

Looking at ∆KAL,

AL/Sin55 = KL/Sin100

50/0.8192 = KL/0.9848

50 × 0.9848 = KL × 0.8192

KL = 49.24/0.8192

KL = 60

AK/Sin25 = AL/Sin 55

AKSin55 = ALSin25

AK × 0.8192 = 0.4226 × 50

AK = 21.13/0.8192

AK = 25.8

2) looking at ∆AOC,

Sin 18 = AD/AC = 18/AC

AC = 18/Sin18 = 18/0.3090

AC = 58.25

Sin 85 = AD/AB = 18/AB

AB = 18/Sin85 = 18/0.9962

AB = 18.1

To determine BC, we would apply Sine rule.

BC/Sin77 = 58.25/Sin85

BCSin85 = 58.25Sin77

BC = 58.25Sin77/Sin85

BC = 58.25 × 0.9744/0.9962

BC = 56.98

7 0
4 years ago
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