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cestrela7 [59]
2 years ago
15

If a triangle has a side that is 5 and a side that is 12, what is the third side

Mathematics
1 answer:
8090 [49]2 years ago
7 0
Is this multiple chose? if so I would like to see the answers. But just using my brain, I would say, 5, or 7. 
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Someone please help me i’m so llst
kicyunya [14]

1+2 that what it is im juts joking idek how to solve that

4 0
2 years ago
Which of the following is a conjugate for 7 + i Square root of 2? (2 points) − 7 + i Square root of 2 7 − i Square root of 2 i S
hammer [34]

Answer:

7-\sqrt{2}i

Step-by-step explanation:

Given number is 7+\sqrt{2}i. We need to find the complex conjugate of the given number.

We will use the general rule to find out the complex conjugate of the number.

The complex conjugate of a+bi will be a-bi

And the complex conjugate of 7+\sqrt{2}i\ became\ 7-\sqrt{2}i

So, the complex conjugate of 7+\sqrt{2}i is 7-\sqrt{2}i

3 0
3 years ago
A line contains points M(1, 3) and N(5, 0). What is the slope of MN? -4/3 -3/4 3/4 4/3
german

Answer:

Step-by-step explanation:

B

5 0
3 years ago
Read 2 more answers
In triangle ABC, a = 4, b = 6, and cos C = − 1/4. What is the length of side c?
shusha [124]

The length of side c would be 8.

Step-by-step explanation:

Given that,

a = 4

b = 6

cosC = -1/4

If we are given two sides and angle, the law of Cosines can be used to find the third side:

c^{2} = a^{2} + b^{2} - 2ab (cos(c))

By inserting the values in the formula, we get

c^{2} = 4^{2} + 6^{2} - 2.4.6 (-\frac{1}{4} )

c^{2} = 16 + 36 + 12

c^{2} = 64

\sqrt{c^{2} } = \sqrt{64}

c = 8.

Therefore, the length of side c would be 8.

7 0
3 years ago
PLEASE HELP ME I WILL GIVE BRAINLIEST TO EVERY SINGLE ANSWER
zepelin [54]

Answer: I believe the answer you are looking for is 33 inches of rain.

Step-by-step explanation:

First you will divide 31 days by 14 days as 2 weeks is 14 days. Which will give you 2.2..... Now multiply your crazy decimal by 15 to get 33.214.... Now round that decimal to 33. There's your answer.

6 0
3 years ago
Read 2 more answers
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