For the first question:Using the distance=rate x time formula (d=rt). Your equation would be y=38x. The 38 comes from the kathryn’s speed(rate).
For the second question: because you know the distance is now 53 substitute 53 for y and solve. 53=38x. Where x represents her time. She travels the 53 miles at a rate of 38mi/h (53 divided by 38) and solve in terms of hours 1.3947or rounded to the nearest tenth 1.4 which in terms of hours is 1 hour 24 minutes.
Answer:
L= 40
W= 35
Step-by-step explanation:
The solution is in the attached file
Depth=15
x=(height(h)*width(w)*hypotenuse(y))/2
x=(3*4*5)/2=(60/2)=30
y=(x(x-h)(x-w)(x-y))^(1/2)
f=(-h^4+2(hw)^2+2(wy)^2-w^4+2(hy)^2-y^4)^(1/2)
f=(-3^4+2(3*4)^2+2(4*5)^2-4^4+2(3*5)^2-5^4)^(1/2)
f=576^(1/2)
f=24
Surface Area= 2f(.5)+(h+w+y)*depth
192=depth*(3+4+5)+24(.5)
180=(3+4+5)*depth
180=(12)(depth)
15=depth
Total socks = 4 + 7+ 11 = 22
Red = 4
White = 7
P(red, then white) = (4/22)(7/21) = 2/33
Answer: 2/33
D/13>-3
You have to multiply 13 in both sides to eliminate the Denominator 13 on the left leaving variable D only.
(D/13)(13) > -3(13)
D > -39
so... D. D > -39
