Answer:
1.4% is the maximum acceptable annual rate of growth such that the population must stay below 24 billion during the next 100 years.
Step-by-step explanation:
We are given the following in the question:
The exponential growth model is given by:

where k is the growth rate, t is time in years and
is constant.
The world population is 5.9 billion in 2006.
Thus, t = 0 for 2006

We have to find the maximum acceptable annual rate of growth such that the population must stay below 24 billion during the next 100 years.
Putting these values in the growth model, we have,

1.4% is the maximum acceptable annual rate of growth such that the population must stay below 24 billion during the next 100 years.
Answer:
2nd - (w - 5)(w + 5)
4th - (-4v - 9)(-4v + 9)
Step-by-step explanation:
1. The first option shows an expression multiplied by its opposite(x -1), so therefore, it does not show the difference of squares
2. The second option does show the difference of squares because it is in the form (a + b)(a - b)
3. The third option is just a square because the same expression is multiplied by itself.
4. The fourth option is the difference of squares because it is in the form (a + b)(a - b). a equals -4v and b equals 9 in this case.
5. The fifth option is not the difference of squares. No term in common in both expressions
6. The sixth option is just a square because the same expression is multiplied by itself.
In all, there are two options that are the difference of squares, the 2nd and 4th.
12 ft I had the question the other day on online school :)
Split the pie into 3 sections and shade only one of them
Let

Differentiating twice gives


When x = 0, we observe that y(0) = a₀ and y'(0) = a₁ can act as initial conditions.
Substitute these into the given differential equation:


Then the coefficients in the power series solution are governed by the recurrence relation,

Since the n-th coefficient depends on the (n - 2)-th coefficient, we split n into two cases.
• If n is even, then n = 2k for some integer k ≥ 0. Then




It should be easy enough to see that

• If n is odd, then n = 2k + 1 for some k ≥ 0. Then




so that

So, the overall series solution is

