Answer:
- secant slopes: -213.5, -187, -145, -113, -85
- tangent slope: -166
Step-by-step explanation:
A) the slope values you have put in your problem statement are correct. As you know, they are computed from ...
(change in gallons)/(change in time)
where the reference point for changes is P. Using the first listed point Q as an example, the secant slope is ...
(3410 -1275)/(5 -15) = 2135/-10 = -213.5 . . . . gallons per minute
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B) The average of the secant slopes for points Q adjacent to P is ...
(-187 +(-145))/2 = -332/2 = -166 . . . . gallons per minute
The tangent slope at point P is estimated at -166 gpm.
Answer:
113.04
Step-by-step explanation:
Answer:

Step-by-step explanation:

Answer: yes is at function
Step-by-step explanation:
because the x is not repeat -1,-1,-3,-4,-5
Answer:
x ≈ 14.30
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Trigonometry</u>
- sin∅ = opposite over hypotenuse
Step-by-step explanation:
<u>Step 1: Define variables</u>
∅ = 39°
opposite leg = 9
hypotenuse = x
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute: sin39° = 9/x
- Multiply <em>x</em> on both sides: xsin39° = 9
- Isolate <em>x</em>: x = 9/sin39°
- Evaluate: x = 14.3011
- Round: x ≈ 14.30