Answer:
At a combined speed of 6 in/min, it takes us 24 mins to clean the wall
Step-by-step explanation:
Since the question did not provide the speed with which each student cleans, we can make assumptions. This is so that we can solve the question before us
Assuming student 1 cleans at a speed of 2 inches per minute, student 2 cleans at a speed of 2½ inches per minute & student 3 cleans at a speed of 1½ inches per minute.
Let's list the parameters we have:
Height of wall (h) = 12 ft, Speed (student 1) = 2 in/min, Speed (student 2) = 2½ in/min, Speed (student 3) = 1½ in/min
Speed of cleaning wall = Height of wall ÷ Time to clean wall
Time to clean wall (t) = Height of wall ÷ Speed of cleaning wall
since students 1, 2 and 3 are working together, we will add their speed together; v = (2 + 2½ + 1½) = 6 in/min
1 ft = 12 in
Time (t) = h ÷ v = (12 * 12) ÷ 6 = 144 ÷ 6
Time (t) = 24 mins
Answer:
Table 1
Step-by-step explanation:
Check Table 1:-
x = -4 gives y = (-4)^2 + 4(-4) = 0
x = -2 gives y = (-2)^2 - 2(-2) = -4
x = 0 gives 0 + 0 = 0
x = 1 gives 1^2 + 4 = 5
That's the one!
Answer:
39/56
Step-by-step explanation:
Answer:
l think it is c
Step-by-step explanation:
