Since there are no specific requirements given other than expression written using exponents, I am just going to give some examples.
1. 5x^2 - 3
2. 8^5 - 15x + 7
3. 15x^10 - 8x^7 + 16x^5 + 17^3 - 4^2 +13x - 2
Total = Principal * e^(rate*years)
where "e" is the mathematical constant 2.71828182828459
Total = 1,600 * e(.046*4)
Total = 1,600 * 2.71828182828459^(.184)
Total = 1,600 *
<span>
<span>
<span>
1.2020158231
</span>
</span>
</span>
Total =
<span>
<span>
<span>
1,923.23</span></span>
</span>
Source:
http://www.1728.org/rate2.htm
Substitution or elimination
The first thing to do in this case is to perform the division and then compare with the simplified expression to determine the values of a, b, c and d.
We have then:
(12xy ^ 3 + 4x ^ 2y ^ 5) / (4xy ^ 2) =
3x (1-1) and ^ (3-2) + x ^ (2-1) and ^ (5-2) =
3x (0) and ^ (1) + x ^ (1) and ^ (3)
Then, comparing with the simplified expression:
3x ^ ay ^ b + 1x ^ cy ^ d
The value of a is
a = 0
answer
the value of a is 0
Answer:
Step-by-step explanation:
There is no pair of real numbers that have a total of -4 and a product of 5. The complex numbers (-2+i) and (-2-i) will meet your requirements.
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If the numbers of interest are 'a' and 'b', they will be zeros of the quadratic whose factored form is ...
(x -a)(x -b) = 0
Expanding that, we find an opportunity to use the given sum and product numbers:
x² -(a+b)x +ab = 0
x² -(-4)x +5 = 0
Rewriting this in vertex form gives ...
(x² +4x +4) +1 = 0
(x +2)² +1 = 0
We can find the values of x by subtracting 1 and taking the square root.
(x +2)² = -1
x +2 = ±√(-1) = ±i
x = -2±i
The two numbers of interest are -2+i and -2-i.
