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Alborosie
4 years ago
11

On a coordinate plane, the coordinates of vertices R and T for a polygon are R(-6,2) and T(5,2). what is the length of side RT o

f the polygon?
Mathematics
1 answer:
MAVERICK [17]4 years ago
8 0
25 units first u go along the x axis then the y then you get ur answer
:))) day
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How to slove 9-6+4×13
riadik2000 [5.3K]
9 - 6 + 4 × 13

First, simplify 4 × 13 to get 52. / Your problem should look like: 9 - 6 + 52
Second, simplify. Subtract 9 - 6 then add 52 onto that. / Your problem should look like: 55

Answer: 55

4 0
3 years ago
Hi i need help asap my parent taught me how to do this equation (x^2-4x)^2+7x^2-28x+12=0 but i still dont understand I really ne
artcher [175]

Answer:

x = 1,  x = 2,  x = 3

Step-by-step explanation:

Hello, please consider the following.

(x^2-4x)^2+7x^2-28x+12=0 \\\\(x(x-4))^2+7x(x-4)+12=0\\\\\text{Let's note }X = x(x-4)\text{ the equation becomes}\\\\X^2+7X+12=0\\\\\text{The sum of the zeroes is -7=-3+(-4) and the product is 12=(-4)*(-3).}\\\\\text{Wo we can factorise.}\\\\X^2+7X+12=X^2+4X+3X+12=X(X+4)+3(X+4)=(X+4)(X+3)=0\\\\X=-4 \ \ or \ \ X=-3

So we need to solve:

x(x-4)=-4 \ \ or \ \ x(x-4)=-3\\\\ x^2-4x-4=(x-2)^2=0 \ \ or \ \ x^2-4x+3=(x-1)(x-3)=0

So, the solutions are x = 2, x = 1, x = 3

Thank you

6 0
3 years ago
Which best describes the strength of the model with an r-value of –0.93?
shtirl [24]

The <em><u>correct answer</u></em> is:

a strong negative correlation

Explanation:

A strong correlation is one that is close to either 1 or -1. -0.93 is very close to -1, so this is a strong correlation.

A negative correlation is one that has a negative r-value. This is a negative r-value, so it is a negative correlation.

7 0
3 years ago
Read 2 more answers
Please Help!!!!! Extra points and brainiest will be given!!!!!
Orlov [11]

Answer:

the big tank can hold 2027.37 m³of water

10 small tanks can be filled

Step-by-step explanation:

r = 11, h = 16

V = (1/3)πr²h

V = (1/3)121π(16)

1936π/3 = 2027.37

2027.37/200 = 10. 136

10 tanks

8 0
3 years ago
Suppose you performed this experiment, and the percentage difference from the accepted value of the density of copper and your v
GREYUIT [131]

Answer:

The answer is 2%

Step-by-step explanation:

Steps to Calculate the Percent Error

Subtract the accepted value from the experimental value.

Take the absolute value of step 1

Divide that answer by the accepted value.

Multiply that answer by 100 and add the % symbol to express the answer as a percentage.

Now let’s try an example problem.

You are given a cube of pure copper. You measure the sides of the cube to find the volume and weigh it to find its mass. When you calculate the density using your measurements, you get 8.78 grams/cm3. Copper’s accepted density is 8.96 g/cm3. What is your percent error?

Solution:

experimental value = 8.78 g/cm3

accepted value = 8.96 g/cm3

Step 1: Subtract the accepted value from the experimental value.

8.78 g/cm3 – 8.96 g/cm3 = -0.18 g/cm3

Step 2: Take the absolute value of step 1

|-0.18 g/cm3| = 0.18 g/cm3

Step 3: Divide that answer by the accepted value.Percent Error Math 3

Step 4: Multiply that answer by 100 and add the % symbol to express the answer as a percentage.

0.02 x 100 = 2

2%

The percent error of your density calculation was 2%.

8 0
3 years ago
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