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mafiozo [28]
4 years ago
11

If you want to track users and sessions across multiple domains, what must you set up?

Computers and Technology
1 answer:
OlgaM077 [116]4 years ago
6 0
The correct answer is:
Cross-domain tracking

Explanation and more info in http://www.certificationanswers.com/en/if-you-want-to-track-users-and-sessions-across-multiple-domai....
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What is the name for software designed to find and open Web documents?
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It's C.spider software purpose is to find/view web documents.
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3 years ago
Is the internet a private place?
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Hey there!

No, the internet is not a private place

I hope this helped! :-)
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Shawn thought that the screen of the block-based program he was using was
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Interface

Explanation:

Definition- "The interface of a particular piece of computer software is its presentation on the screen and how easy it is to operate. <em>...the development of better user interfaces.</em>"

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Rafael needs to add a title row to a table that he has inserted in Word. What should he do? Use the alignment options. Use the M
raketka [301]

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Answer is C

Explanation:

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3 years ago
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You also learn in class that one kilobyte of computer memory will hold about 2/3 of a page of typical text (without formatting).
Travka [436]

Answer:

The flashdrive can hold 35389 400-pages-books

Explanation:

If \frac{2}{3} of a page occupies 1 kB of memory, we can calculate how much memory a book will take

2/3kB=1 page\\ x kB=400 pages\\266.67 kB=400 pages

Now that we know that a book average file size is about 266,67 kB, we calculate how many of them can a 9 GB flash drive hold.

To do the calculation, we have to know how many kilobytes are in 9 gigabytes.

There is 1024 kilobytes in a megabyte, and 1024 megabytes in a gigabyte, so:

Memory_{in _kilobytes}^{} =1024\frac{kilobytes}{megabytes} *1024\frac{megabytes}{gigabytes}*9=9437184 kilobytes

Finally, knowing the average file size of a book and how much memory in kilobytes the 9 GB flash drive holds, we calculate how many books can it hold.

Books=\frac{Flash drive memory}{Filesize of a book} =\frac{9437184kilobytes}{266.67\frac{kilobytes}{book} } =35389,4 books

The flashdrive can hold 35389 400-pages-books, or 14155776 pages of typical text.

8 0
4 years ago
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