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svet-max [94.6K]
3 years ago
15

How do I know my points

Mathematics
2 answers:
ioda3 years ago
5 0

Answer:

I think they are shown on the right next to your profile

Step-by-step explanation:

Step2247 [10]3 years ago
5 0

Answer:TOP LEFT ON YOUR SCREEN

Step-by-step explanation:

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Which of the following are solutions to the equation below? check all that apply x^2+4x-9=x+1
Aleks04 [339]
The answer is C and D only
6 0
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A plant mesures 3 yards and 10 inches what is the height of the plant mesured in inches
NARA [144]
The height of the plant it 63 yards 5 inches and 5
6 0
3 years ago
To celebrate 25 years in business, the furniture store is having a 25% off sale on all their furniture. Estimate the new price b
ICE Princess25 [194]

Answer:

Step-by-step explanation:

159.39(1-25/100)

159.39(100-25)/100

159.39(75)/100

159.39(0.75)

$119.54

5 0
3 years ago
Find the annual interest rate
patriot [66]

The annual interest rate is 6.2%.

Solution:

Given data:

Interest = $310

Principle = $1000

Time = 5 years

To find the annual interest rate:

<u>Simple Interest formula:</u>

$S.I=\frac{PRT}{100}

Substitute the given values in the formula, we get

$310=\frac{1000\times R \times5}{100}

Do cross multiplication.

$310 \times 100=1000\times R \times5

Divide both sides of the equation by 1000, we get

$\frac{310 \times 100}{1000}=\frac{1000\times R \times5}{1000}

31=R\times 5

Divide by 5 on both sides of the equation, we get

$\frac{31}{5}=\frac{R\times 5}{5}

6.2=R

R = 6.2%

Hence the annual interest rate is 6.2%.

8 0
3 years ago
What is the average distance between the parabola y=30x(20-x) and the x-axis on the interval [0, 20]?
Anni [7]

Answer: the average distance between the parabola is 2000

Step-by-step explanation:

Given that;

y = 30x(20 - x) and the x-axis on the interval [0, 20]

f(x) = y = 30x(20 - x); [0, 20] and a=0, b=20

the average distance between the parabola will be

Average value = 1/20-0 ²⁰∫₀ 30x(20-x) dx

= 1/20 ²⁰∫₀ (600x-30x²) dx

= 1/20 [(600x)/2 - (30x³)/3]₀²⁰

= 1/20 [300x - 10x³]₀²⁰

inputting the limits, we get

= 1/20 [(300 × 20 × 20 - 10 × 20 × 20 × 20) - 0 - 0]

=  1/20 ( 120000 - 80000)

= 0.05 × 40000

<h2>= 2000</h2>

Therefore the average distance between the parabola is 2000

<h3 />
5 0
3 years ago
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