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Serjik [45]
3 years ago
8

Multiply the following fractions. Reduce your answer to lowest terms. 3/7 4/5

Mathematics
2 answers:
dmitriy555 [2]3 years ago
6 0
3/7 * 4/5  = (3*4) / (7*5) =  12 /35 (answer)
kondor19780726 [428]3 years ago
3 0
The product of 3/7 • 4/5 is 12/35
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I WILL CHOOSE BRAINLIEST as long as it LOOKS correct<br><br> Solve 3 ( x − 4 ) = 12 x
omeli [17]

Answer:

The answer is (-4/3)

Step-by-step explanation:

3(x − 4) = 12x

Multiply (x – 4) by 3 we get,

3(x – 4) = 12x

3x – 12 = 12x

3x – 12x – 12 + 12 = 12x – 12x + 12

-9x = 12

-9x/(-9) = -12/9

x = -4/3

Thus, The value of x is -4/3

<u>-TheUnknownScientist 72</u>

4 0
2 years ago
Read 2 more answers
A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.
mezya [45]
1. Divide wire b in parts x and b-x. 

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= \frac{1}{2}sin60^{o}side*side=   \frac{1}{2} \frac{ \sqrt{3} }{2}  (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}
A=\frac{ \sqrt{3} }{36}(b-x)^{2}=\frac{ \sqrt{3} }{36}( b^{2}-2bx+ x^{2}  )=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6

3. Let x be the circumference of the circle.

 2 \pi r=x

so r= \frac{x}{2 \pi }

Area of circle = \pi  r^{2}= \pi  ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2}  }* x^{2} = \frac{1}{4 \pi } x^{2}

4. Let f(x)=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)=\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0

\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0

(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b

x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }

6. So one part is \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) } and the other part is b-\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }

4 0
3 years ago
Read 2 more answers
Which one is the right answer
Jobisdone [24]

Answer: A. f(g(x)) =x and g(f(x))=x and f and g are inverses.

Step-by-step explanation:

A function <em>g</em> is the inverse of function <em>f</em> if

<em>f(g(x)) = g(f(x))=x</em>

Given: f(x)=  x+4 , g(x) = x-4

f(g(x)) = f(x+4) = (x-4)+4

= x-4+4 = x

i.e. f(g(x)) =x

g(f(x))= g(x-4) = (x-4)+4 =x

i.e. g(f(x))=x

Hence, f(g(x)) =x and g(f(x))=x and f and g are inverses.

8 0
3 years ago
A linear set of points with a unique starting point and extending infinitely in one direction what term matches the definition?
bija089 [108]

Answer:- Option A "ray" is the right term which matches with the definition.


Explanation:-

A ray is a line that has one fixed endpoint, and extends infinitely along the line from the fixed endpoint.

Therefore, the term which matches with the given definition is "ray".

Thus A linear set of points with a unique starting point and extending infinitely in one direction is called a ray.


5 0
3 years ago
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Solve and find X. <br> Question says 5-x / 2 = 2x-7
poizon [28]

Answer:

x = 3.8

Step-by-step explanation:

The equation is (5 - x) / 2 = 2x - 7

Multiply both sides by 2:

5 - x = 4x - 14

Add 14 to both sides:

19 - x = 4x

Add x to both sides:

19 = 5x

Divide both sides by 5 to isolate x:

3.8 = x

Therefore, x = 3.8.

7 0
3 years ago
Read 2 more answers
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