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nata0808 [166]
3 years ago
10

Sorry for lack of a better picture, I really really need help please!

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
4 0
B. 6.72the answer is B 6.72
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What is the linear function equation represented by the graph? Graph of a line on a coordinate plane. The horizontal x-axis rang
salantis [7]
The 2-point form of the equation of a line is
.. y = (y2 -y1)/(x2 -x1)*(x -x1) +y1
For your points (x1, y1) = (0, 3) and (x2, y2) = (3, 5), this is
.. y = (5 -3)/(3 -0)*(x -0) +3
.. y = (2/3)x +3

Written as a function, it is
.. f(x) = (2/3)x +3

8 0
3 years ago
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Help can you please solve this.
saveliy_v [14]

Answer:

x= -2

Step-by-step explanation:

7x+26+5x=2

7x+5x=12x

12x=2-26

12x= -24

(divide both sides by 12)

x= -2

5 0
3 years ago
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Xsquared+ 12x what number should be added to make it a perfect square trinomial? 36,6,12,or 18
Sidana [21]
18 is the answer im pretty sure if its wrong im sorry
4 0
3 years ago
What would be the most logical first step for solving this quadratic equation?
Sav [38]

Answer:

D. Subtract 4 from both sides

Explanation:

I just learned about quadratic equations in school. The first step of solving quadratic equations is to make sure it is in standard form and equal to 0.

Standard form:

ax^2 + bx + c = 0

4 0
2 years ago
Theorem: The segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length. A two-c
natali 33 [55]

Answer:  By the slope formula.

Step-by-step explanation:

Given: ABC is a triangle (shown below),

In which A≡(6,8), B≡(2,2) and C≡(8,4)

And, D and E are the mid points of the line segments AB and BC respectively.

Prove: DE║AC and DE = AC/2

Proof:

Since, And, D and E are the mid points of the line segments AB and BC respectively.

Therefore, By mid point theorem,

coordinate of D are (\frac{2+6}{2} , \frac{2+8}{2} ) = (\frac{8}{2} , \frac{10}{2} )= (4,5)

Coordinate of E are  (\frac{2+8}{2} , \frac{2+4}{2} ) = (\frac{10}{2} , \frac{6}{2} )= (5,3)

By the distance formula,

DE=\sqrt{(5-4)^2+(3-5)^2}=\sqrt{5}

AC=\sqrt{(8-6)^2+(4-8)^2}=2\sqrt{5}

By the slope formula,

Slope of AC = \frac{4-8}{8-6} = \frac{-4}{2} = -2

Slope of DE =  \frac{3-5}{5-4} = \frac{-2}{1} = -2


            Statement                                              Reason

1. The coordinate of D are (4,5)  and           1. By the midpoint formula

the coordinate of  E are (5,3)

2. The length of DE = √5                            2. By the Distance formula

The length AC = 2√5 ⇒ Segment DE

is half the length of segment AC

3. The slope of DE = -2 and the                3. By the slope formula

slope of AC = -2

4. DE║AC                                                   4. Slopes of parallel lines are equal


7 0
3 years ago
Read 2 more answers
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