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castortr0y [4]
3 years ago
8

What is 11 divided by 7?

Mathematics
2 answers:
katovenus [111]3 years ago
7 0

The answer is 1.57. Hope this helps!

sesenic [268]3 years ago
4 0

11/7 = 1.57

Hope this Helps!!

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rachel jogged along a trail that was 1/4 of a mile long. She jogged along the trail 8 times. how many miles did rachel jog?
____ [38]
To solve for how many miles Rachel jogged if she jogged a 1/4 mile trail 8 times, we simply need to multiply the distance she ran each time by the amount of times she ran it.

1/4 * 8 = 2

Rachel jogged 2 miles.
Hope that helped =)
4 0
3 years ago
What set of reflections would carry trapezoid ABCD onto itself? (1 point)
blondinia [14]

Answer:

Umm text me at (623) 300-4928 if you find the answer

3 0
3 years ago
on a certain planet, objects weight about 7/12 of what they weigh on earth. an object weights 13 5/12 pounds on the planet. solv
Cloud [144]
Although the concept here is physics, the solution is technically just algebra. You have two situations that are related to each other which can be expressed in equation form. Actually, the equation is already given which is <span>7/12 w= 13 5/12. So, basically, all you have to do is solve for w.

Let's simplify 13 5/12 first into an improper fraction.You do this by multiplying the denominator with the whole number and adding to it the numerator. This will be your new numerator, The denominator would still be 12. So, this is equal to (12*13 + 5)/12 = 161/2. Then,

(7/12) w = 161/12

By cross multiplication,

7*12*w = 161*12
w = 161/7 = 23

Therefore, w = 23 pounds which is the weight of the object on Earth.


</span>
8 0
3 years ago
For a class project, a teacher cuts out 15 congruent
True [87]

Answer:

60 -047 = 13 in²

Step-by-step explanation:

Paper area: 6 x 10 = 60

15 circles, each circle has diameter: 6 /3 or 10 /5 = 2

each circle area: πr² = 3.14 x 1² = 3.14

15 circles: 3.14 x 15 = 47.1

paper wasted: 60 - 47.1 ≈ 13 in²

5 0
4 years ago
Use the discriminate to determine the number and the nature of the solutions of the giving equation
MatroZZZ [7]

Answer:

Since b^2 -4ac = -31 we have 2 complex roots

Step-by-step explanation:

2x^2+ 5x+7=0​

The discriminant is b^2 -4ac

when the equation is ax^2 +bx+c

so a =2   b=5 and c=7

(5)^2 - 4(2)(7)

25 - 56

-31

If b^2 -4ac > 0 we have 2 real distinct roots

If b^2 -4ac = 0 we have one real root

If b^2 -4ac < 0 we have two complex root

Since b^2 -4ac = -31 we have 2 complex roots

8 0
3 years ago
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