=2ab - 20a -5a +10 -ab - b
= ab - 25a - b + 10
A quadratic with roots at 8 and 5 is f(x) = x^2 +12x + 20
In order to find an equation given roots you can create statements that equal 0 in order to create parenthesis. For instance we know x = 8 at one point. So, we can solve that to equal 0.
x = -2 ----> add 2 to both sides
x + 2 = 0
We can do the same for the other zero.
x = -10 ----> add 10 to both sides
x + 10 = 0
Now that we have both of these, we can multiply these two things together. This will give us the function we need.
f(x) = (x + 2)(x + 10)
f(x) = x^2 + 10x + 2x + 20
f(x) = x^2 + 12x + 20
The domain of the function given above is the value of w that would make it reasonable. Among the numbers, w cannot be zero because that would make the fraction 70/0 undefined. So the domain of the function is from negative infinity to positive infinity but not zero.
Since there are only 2 numbers in the sequence that are even or greater than 78 it's 2/5th or 0.4
Answer:
Step-by-step explanation: